Take 5/6 x 4/1 and multiply 5x4 and 6x1 to get 20/6. 6 goes into 20 3 times, with 2/6 leftover. Reduce 2/6 to 1/3 and your final answer is 3 1/3.
146 area of trapazoid 90
area of triangle 56
Answer:
12.252, 12.26, 12.387, 12.4
Step-by-step explanation:
These are the only numbers in a series that are always increasing.
The first series (0.13, 0.31, 0.04, 0.5) and fourth series (6.009, 6.015, 6.241, 6.2) all have an area where they decrease (0.04 and 6.2 respectively).
The second series of numbers is in decreasing order, rather than increasing order. This can not be the answer.
Let h represent the height of the trapezoid, the perpendicular distance between AB and DC. Then the area of the trapezoid is
Area = (1/2)(AB + DC)·h
We are given a relationship between AB and DC, so we can write
Area = (1/2)(AB + AB/4)·h = (5/8)AB·h
The given dimensions let us determine the area of ∆BCE to be
Area ∆BCE = (1/2)(5 cm)(12 cm) = 30 cm²
The total area of the trapezoid is also the sum of the areas ...
Area = Area ∆BCE + Area ∆ABE + Area ∆DCE
Since AE = 1/3(AD), the perpendicular distance from E to AB will be h/3. The areas of the two smaller triangles can be computed as
Area ∆ABE = (1/2)(AB)·h/3 = (1/6)AB·h
Area ∆DCE = (1/2)(DC)·(2/3)h = (1/2)(AB/4)·(2/3)h = (1/12)AB·h
Putting all of the above into the equation for the total area of the trapezoid, we have
Area = (5/8)AB·h = 30 cm² + (1/6)AB·h + (1/12)AB·h
(5/8 -1/6 -1/12)AB·h = 30 cm²
AB·h = (30 cm²)/(3/8) = 80 cm²
Then the area of the trapezoid is
Area = (5/8)AB·h = (5/8)·80 cm² = 50 cm²
R=x(A+B)
divide both sides by x
R/x=A+B
minus B both sides
(R/x)-B=A
A=(R/x)-B
