Answer:
P(X= k) = (1-p)^k-1.p
Step-by-step explanation:
Given that the number of trials is
N < = k, the geometric distribution gives the probability that there are k-1 trials that result in failure(F) before the success(S) at the kth trials.
Given p = success,
1 - p = failure
Hence the distribution is described as: Pr ( FFFF.....FS)
Pr(X= k) = (1-p)(1-p)(1-p)....(1-p)p
Pr((X=k) = (1 - p)^ (k-1) .p
Since N<=k
Pr (X =k) = p(1-p)^k-1, k= 1,2,...k
0, elsewhere
If the probability is defined for Y, the number of failure before a success
Pr (Y= k) = p(1-p)^y......k= 0,1,2,3
0, elsewhere.
Given p= 0.2, k= 3,
P(X= 3) =( 0.2) × (1 - 0.2)²
P(X=3) = 0.128
Answer:
A=b(1/2b-1)
112ft^2
Step-by-step explanation:
-Write the equation in factored form: A= b (1/2 b -1 )
-Supposed the base of the flower bed is 16 feet. What will the area be:
b=16 feet
Formula is A=1/2(1/2b-1)
Replace the b with 16
A=1/2 (16)^2 - 16
A=1/2 (256)-16
A=256/2 - 16
A=128-16
A=112 ft^2
The area will be 112 ft^2
Umm , what is this for? do you need help on anything or? lol
Hmm, I believe the answer is 80%.
It is a decrease.
30 - 6 = 24.
24/30 = 80% decrease from Wednesday.
Answer:
The chance of getting a sample proportion of 70% or greater is 0.026.
Step-by-step explanation:
We are given that a poll shows that 50% of students play sports
.
A random sample of 20 students showed that 70% of them play sports.
Let 
= sample proportion of students who play sports
The z-score probability distribution for the sample proportion is given by;
Z = 
~ N(0,1)
where, = sample proportion of students who play sports = 70%
p = population proportion of students who play sports = 50%
n = sample of students = 20
Now, the chance of getting a sample proportion of 70% or greater is given by = P( 
70%)
P( 70%) = P( 
) = P(Z 1.95) = 1 - P(Z < 1.95)
= 1 - 0.97441 = <u>0.026</u>
The above probability is calculated by looking at the value of x = 1.95 in the z-table which has an area of 0.97441.
Hence, the chance of getting a sample proportion of 70% or greater is 0.026.
