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Alekssandra [29.7K]
3 years ago
7

7/8-1/2 it’s a homework question and I can’t get it

Mathematics
1 answer:
kaheart [24]3 years ago
5 0

Answer:

the answer is 3/8

Step-by-step explanation:

multiply 7 by 2, and get 14

multiply 1 by 8, and get 8

give both terms new denominators which will be 16

The new fraction will be  \frac{14}{16} - \frac{8}{16}

Now you can subtract the numerators which will give you 6/16

Now you would simplify the fraction

Divide the fraction by 2 and you get 3/8 which is your answer

Hope this helps:)

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What is the product of −214 and −412?
nlexa [21]
-214 x -412 = 88,168

“Product” means the answer you get from multiplying two or more numbers together.
* Tip: A negative number times another negative number equals a positive.

Hope this helps!
8 0
3 years ago
Sean reads 1 1/2 pages in 3 1/3 minutes. What is his average page per minute?
Helga [31]

Answer:

9/20 pages per minute.

Step-by-step explanation:

4 0
3 years ago
Simplify the expression<br>5-2(9)|+9^2÷3​
Delicious77 [7]

Answer:

14

Step-by-step explanation:

Simplify the following:

5 - 2×9 + 9^2/3

Hint: | Evaluate 9^2.

9^2 = 81:

5 - 2×9 + 81/3

Hint: | Reduce 81/3 to lowest terms. Start by finding the GCD of 81 and 3.

The gcd of 81 and 3 is 3, so 81/3 = (3×27)/(3×1) = 3/3×27 = 27:

5 - 2×9 + 27

Hint: | Multiply -2 and 9 together.

-2×9 = -18:

5 + -18 + 27

Hint: | Evaluate 5 + 27 using long addition.

| 1 |  

| 2 | 7

+ | | 5

| 3 | 2:

32 - 18

Hint: | Subtract 18 from 32.

| 2 | 12

| 3 | 2

- | 1 | 8

| 1 | 4:

Answer: 14

5 0
4 years ago
Unit 8 right triangles and trigonometry homework 3 similar right triangles and geometric mean
Ugo [173]

The right triangles that have an altitude which forms two right triangles

are similar to the two right triangles formed.

Responses:

1. ΔLJK ~ ΔKJM

ΔLJK ~ ΔLKM

ΔKJM ~ ΔLKM

2. ΔYWZ ~ ΔZWX

ΔYWZ ~ ΔYZW

ΔZWX ~ ΔYZW

3. x = <u>4.8</u>

4. x ≈ <u>14.48</u>

5. x ≈ <u>11.37</u>

6. G.M. = <u>12·√3</u>

7. G.M. = <u>6·√5</u>

<u />

<h3>What condition guarantees the similarity of the right triangles?</h3>

1. ∠LMK = 90° given

∠JMK + ∠LMK  = 180° linear pair angles

∠JMK = 180° - 90° = 90°

∠JKL ≅ ∠JMK All 90° angles are congruent

∠LJK ≅ ∠LJK reflexive property

  • <u>ΔLJK is similar to ΔKJM</u> by Angle–Angle, AA, similarity postulate

∠JLK ≅ ∠JLK by reflexive property

  • <u>ΔLJK is similar to ΔLKM</u> by AA similarity

By the property of equality for triangles that have equal interior angles, we have;

  • <u>ΔKJM ~ ΔLKM</u>

2. ∠YWZ ≅ ∠YWZ by reflexive property

∠WXZ ≅ ∠YZW all 90° angle are congruent

  • <u>ΔYWZ is similar to ΔZWX</u>, by AA similarity postulate

∠XYZ ≅ ∠WYZ by reflexive property

∠YXZ ≅ ∠YZW all 90° are congruent

  • <u>ΔYWZ is similar to ΔYZW</u> by AA similarity postulate

Therefore;

  • <u>ΔZWX ~ ΔYZW</u>

3. The ratio of corresponding sides in similar triangles are equal

From the similar triangles, we have;

\dfrac{8}{10} = \mathbf{ \dfrac{x}{6}}

8 × 6 = 10 × x

48 = 10·x

  • x = \dfrac{48}{10} = \underline{4.8}

3. From the similar triangles, we have;

\mathbf{\dfrac{20}{29}} = \dfrac{x}{21}

20 × 21 = x × 29

420 = 29·x

  • x = \dfrac{420}{29 } \approx \underline{14.48}

4. From the similar triangles, we have;

\mathbf{\dfrac{20}{52}} = \dfrac{x}{48}

20 × 48 = 52 × x

  • x = \dfrac{20 \times 48}{52}  = \dfrac{240}{13}  \approx \underline{18.46}

5. From the similar triangles, we have;

\mathbf{\dfrac{13.2}{26}} = \dfrac{x}{22.4}

13.2 × 22.4 = 26 × x

  • x = \dfrac{13.2 \times 22.4}{26} \approx \underline{ 11.37}

6. The geometric mean, G.M. is given by the formula;

G.M. = \mathbf{\sqrt[n]{x_1 \times x_2 \times x_3  ... x_n}}

The geometric mean of 16 and 27 is therefore;

  • G.M. = \sqrt[2]{16 \times 27}  = \sqrt[2]{432} = \sqrt[2]{144 \times 3} = \mathbf{12 \cdot \sqrt{3}}

  • The geometric mean of 16 and 27 is <u>12·√3</u>

<u />

7. The geometric mean of 5 and 36 is found as follows;

G.M. = \sqrt[2]{5 \times 36}  = \sqrt[2]{180} = \sqrt[2]{36 \times 5} = \mathbf{ 6 \cdot \sqrt{5}}

  • The geometric mean of 5 and 36 is <u>6·√5</u>

Learn more about the AA similarity postulate and geometric mean here:

brainly.com/question/12002948

brainly.com/question/12457640

7 0
3 years ago
How did they get that answer? please answer
OverLord2011 [107]

Answer:

Look at my explanation

Step-by-step explanation:

The circumference of a circle is 2πr, so you can set it up like this since the circumference was 22π.

2πr = 22π

divide both sides by 2

πr = 11π

divide both sides by π

you get r = 11

So your radius is 11.

To find the area, you must do πr^2 ("^2" means squared)

if you substitute 11 for r you get

11π^2

you can do 11 squared first

11^2 = 121

the area of the circle = 121π

Keep in mind that they said to use 3.14 for π

so you can do 121 x 3.14

Final Answer: 379.94

3 0
3 years ago
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