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2 years ago

Please look at pic below. Will give 100 points!!!!! NUMBER 2 I NEED HELP

Mathematics

2 answers:

Romashka-Z-Leto [24]2 years ago

7 0

here are your answers!

It is assumed the base of the prism is a square wit side of 5 cm.

The volume is:

V = Bh = 250 cm³

The base is:

B = a² = 5² = 25 cm²

Find h:

h = V/B

h = 250/25 = 10cm

natta225 [31]2 years ago

3 0

Answer:

It is assumed the base of the prism is a square wit side of 5 cm.

The volume is:

V = Bh = 250 cm³

The base is:

B = a² = 5² = 25 cm²

Find h:

h = V/B
h = 250/25 = 10cm

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Given the figure, if ∠ABC is 20° and C is the center of the circle, what is the measure of the central angle ∠ACB? A) 40° B) 70°

kramer

Answer:

D) 140°

Step-by-step explanation:

The total number of degrees in a triangle is 180. Since both sides of the triangle are the radius of the circle, the triangle is isosceles. Therefore the two opposite angles are equal. Thus, the central angle is 180° − 2(20°) = 140°.

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2 years ago

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1/8 gram of copper and 1/3 of silicone is used to manufacture 30 headphones. how much silicone is used in each pair of headphone

FinnZ [79.3K]

Answer:

0.0111 grams with the one repeating

Step-by-step explanation:

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2 years ago

The frist brand is 30% and the second on is 55% in order to obtain 30 gallons of mixture that contains 35% how many gallons of e

snow_tiger [21]

yeet

first brand quantity is x

2nd brand quantity is y

x+y=30

0.3x+0.55y=0.35(30) or 0.3x+0.55y=10.5

solve for x and y

multiply first equation by -0.3

-0.3x-0.3y=-9

add to 2nd equation

0.3x-0.3y=-9

0.3x+0.55y=10.5 +

0x+0.25y=1.5

0.25y=1.5

divide both sides by 0.25

y=6

sub back

x+y=30

x+6=30

x=24

you need 24 gallons of the first brand and 6 gallons of the 2nd brand

4 0

2 years ago

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Solve for y where y(2)=2 and y'(2)=0 by representing y as a power series centered at x=a

Crank

I'll assume the ODE is actually

$y''+(x-2)y'+y=0$

Look for a series solution centered at $x=2$ , with

$y=\displaystyle\sum_{n\ge0}c_n(x-2)^n$

$\implies y'=\displaystyle\sum_{n\ge0}(n+1)c_{n+1}(x-2)^n$

$\implies y''=\displaystyle\sum_{n\ge0}(n+2)(n+1)c_{n+2}(x-2)^n$

with $c_0=y(2)=2$ and $c_1=y'(2)=0$ .

Substituting the series into the ODE gives

$\displaystyle\sum_{n\ge0}(n+2)(n+1)c_{n+2}(x-2)^n+\sum_{n\ge0}(n+1)c_{n+1}(x-2)^{n+1}+\sum_{n\ge0}c_n(x-2)^n=0$

$\displaystyle\sum_{n\ge0}(n+2)(n+1)c_{n+2}(x-2)^n+\sum_{n\ge1}nc_n(x-2)^n+\sum_{n\ge0}c_n(x-2)^n=0$

$\displaystyle2c_2+c_0+\sum_{n\ge1}(n+2)(n+1)c_{n+2}(x-2)^n+\sum_{n\ge1}nc_n(x-2)^n+\sum_{n\ge1}c_n(x-2)^n=0$

$\displaystyle2c_2+c_0+\sum_{n\ge1}\bigg((n+2)(n+1)c_{n+2}+(n+1)c_n\bigg)(x-2)^n=0$

$\implies\begin{cases}c_0=2\\c_1=0\\(n+2)c_{n+2}+c_n=0&\text{for }n>0\end{cases}$

If $n=2k$ for integers $k\ge0$ , then

$k=0\implies n=0\implies c_0=c_0$

$k=1\implies n=2\implies c_2=-\dfrac{c_0}2=(-1)^1\dfrac{c_0}{2^1(1)}$

$k=2\implies n=4\implies c_4=-\dfrac{c_2}4=(-1)^2\dfrac{c_0}{2^2(2\cdot1)}$

$k=3\implies n=6\implies c_6=-\dfrac{c_4}6=(-1)^3\dfrac{c_0}{2^3(3\cdot2\cdot1)}$

and so on, with

$c_{2k}=(-1)^k\dfrac{c_0}{2^kk!}$

If $n=2k+1$ , we have $c_{2k+1}=0$ for all $k\ge0$ because $c_1=0$ causes every odd-indexed coefficient to vanish.

So we have

$y(x)=\displaystyle\sum_{k\ge0}c_{2k}(x-2)^{2k}=\sum_{k\ge0}(-1)^k\frac{(x-2)^{2k}}{2^{k-1}k!}$

Recall that

$e^x=\displaystyle\sum_{n\ge0}\frac{x^k}{k!}$

The solution we found can then be written as

$y(x)=\displaystyle2\sum_{k\ge0}\frac1{k!}\left(-\frac{(x-2)^2}2\right)^k$

$\implies\boxed{y(x)=2e^{-(x-2)^2/2}}$

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3 years ago

What will it cost to tile a rectangular floor measuring 299 feet by by 34 feet if the tile costs $ 11 per square foot?

AnnZ [28]

First, you need to find the area of the room.

299×34=10166

Once you found the area of the room, you need to find the cose of the tile.

10166×11=111826

It will cost $111,826 to cover 10166 square feet.

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2 years ago