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bazaltina [42]
2 years ago
15

Please help by the way this is differentiation ​

Mathematics
1 answer:
Nat2105 [25]2 years ago
7 0

Answer:

First i found out the gradient then used the equation of a straight line formula to find the tangent

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A zookeeper weighed an African elephant to be 9x10^3 pounds and an African lion to be 4x10^2 pounds. How many times greater is t
maria [59]
Answer:  22.5 .  The weight of the elephant is "22.5 times greater" than                              the weight of the lion.
_________________________________________________________
Explanation:
_________________________________________________________

(weight of lion) * (x) = (eight of the elephant)  ;  Solve for "x" .
_____________________________________________________
   → Divide each side of the equation by "(weight of lion)" ;
  to isolate "x" on one side of the equation ; and to solve for "x" ;
_________________________________________________________
    
   → (weight of lion)*(x) / (weight of lion) = (weight of the elephant) /
                                                           (weight of lion) ;
________________________________________________________
     →  x  = (weight of the elephant) / (weight of lion) ;
__________________________________________________________
     →  Plug in our "given values" ; and solve for "x" ;
__________________________________________________________
     →  x = (<span>9*10</span>³) / (4*10²) =  (9*10⁽³⁻²⁾) / 4  =  (9*10¹) / 4  ;
__________________________________________________________  
     →  x =  90 /4 = 25/2  = 22.5 ; which is our answer.
__________________________________________________________
4 0
3 years ago
What does not represent the quotient of 17 divided by 10?
amm1812
17-10= j      i really don't know i just guessed  
7 0
3 years ago
9.4 The heights of a random sample of 50 college stu- dents showed a mean of 174.5 centimeters and a stan- dard deviation of 6.9
gladu [14]

Answer:  a) (176.76,172.24), b) 0.976.

Step-by-step explanation:

Since we have given that

Mean height  = 174.5 cm

Standard deviation = 6.9 cm

n = 50

we need to find the 98% confidence interval.

So, z = 2.326

(a) Construct a 98% confidence interval for the mean height of all college students.

x\pm z\times \dfrac{\sigma}{\sqrt{n}}\\\\=(174.5\pm 2.326\times \dfrac{6.9}{\sqrt{50}})\\\\=(174.5+2.26,174.5-2.26)\\\\=(176.76,172.24)

(b) What can we assert with 98% confidence about the possible size of our error if we estimate the mean height of all college students to be 174.5 centime- ters?

Error would be

\dfrac{\sigma}{\sqrt{n}}\\\\=\dfrac{6.9}{\sqrt{50}}\\\\=0.976

Hence, a) (176.76,172.24), b) 0.976.

8 0
3 years ago
(r/s)(3) = ?<br><br> please help.
MissTica

Answer:

\frac{3r}{s}

4 0
3 years ago
Use scientific notation to determine the answer :
vampirchik [111]
A= 1.5 × 10^10




Hope that helps
3 0
3 years ago
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