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Nezavi [6.7K]
2 years ago
11

Please help me with this math problem!! It's due tonight!! :)

Mathematics
2 answers:
Fudgin [204]2 years ago
3 0

Answer:

x = 7

Step-by-step explanation:

5x - 1 + 8x + 5 = 95

13x + 4 = 95

13x = 91

x = 7

melomori [17]2 years ago
3 0
<h2>♪Answer : </h2>

Triangle in 95° so x is

»8x + 5° + 5x - 1° = 95°

»13x + 4° = 95°

»13x = 91°

»x = 91°/13

»x = 7°✅

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Can anyone help? Please.
lisabon 2012 [21]

Answer:

29.9

Step-by-step explanation:

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3 0
3 years ago
3(4x + 5) = 12 Which of the following correctly shows the beginning steps to solve this equation?
Contact [7]
The correct answer is A.

Here is the completed problem:

3(4x+5)=12

Distributive property.

3(4x+5)=12

Simplify

12x+15=12

Subtract 15 from both sides.

12x+15−15=12−15

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8 0
3 years ago
How do i write 720,080 in expanded form with exponents
max2010maxim [7]
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4 0
3 years ago
Find the derivative dy / dx for y = x^3 - 5x / x^2 - 1
soldier1979 [14.2K]

Use\\\\\left(\dfrac{h(x)}{g(x)}\right)'=\dfrac{h'(x)g(x)-h(x)g'(x)}{[g(x)]^2}\\\\\text{We have}\\\\h(x)=x^3-5x\to h'(x)=3x^2-5\\\\g(x)=x^2-1\to g'(x)=2x\\\\f(x)=\dfrac{x^3-5x}{x^2-1}\to f'(x)=\left(\dfrac{x^3-5x}{x^2-1}\right)'\\\\=\dfrac{(x^3-5x)'(x^2-1)-(x^3-5x)(x^2-1)'}{(x^2-1)^2}\\\\=\dfrac{(3x^2-5)(x^2-1)-(x^3-5x)(2x)}{(3x^2-5)^2}\\\\=\dfrac{3x^4-3x^2-5x^2+5-2x^4+10x^2}{(x^2-1)^2}\\\\=\dfrac{x^4+2x^2+5}{(x^2-1)^2}\\\\Answer:\ \left(\dfrac{x^3-5x}{x^2-1}\right)'=\dfrac{x^4+2x^2+5}{(x^2-1)^2}

8 0
3 years ago
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