<h2><u>Q</u><u>u</u><u>e</u><u>s</u><u>t</u><u>i</u><u>o</u><u>n</u>:-</h2>
Donna borrowed $10,500 at a simple interest rate of 4% for 3 years to buy her new car. How much interest would Donna pay and how much is the car altogether ?
<h2><u>A</u><u>n</u><u>s</u><u>w</u><u>e</u><u>r</u>:-</h2>
<h3>Given:-</h3>
Principal (P) = $10,500
Rate of interest (r) = 4%
Time (t) = 3 years
<h3>To Find:-</h3>
Interest of Donna and amount of car altogether.
<h2>Solution:-</h2>
We know,
I = 
I = 
I = $1260
Now,
Amount of the car = $ (10,500 + 1260)
= $ 11,760
<h3><u>$</u><u>1</u><u>2</u><u>6</u><u>0</u> interest would Donna pay and <u>$</u><u>1</u><u>1</u><u>,</u><u>7</u><u>6</u><u>0</u> is the car altogether. [Answer]</h3>
Answer:
25
Step-by-step explanation:
Let's simplify this, while still doing it.
3 + 2(4 + 7)
3 + 2(11)
3 + 22
25.
the answer is 25!!
Answer:
The last one is correct: 3(x+5)=3 . X + 3 . 5
Answer:
Step-by-step explanation:
Part 1
P(z < -1.45)
Using the z score table
P =
Part 2
We solve using z score formula
z = (x-μ)/σ, where x is the raw score, μ is the population mean, and σ is the population standard deviation.
a) P(X >52)
x = 52
Mean = 60
Standard deviation = 8
z = 52 - 60/8
z = -1
P-value from Z-Table:
P(x<52) = 0.15866
P(x>52) = 1 - P(x<52) = 0.84134
b) P(48 < x < 64)
Since g(x) varies with x, therefore:
g(x) = k/x where k is a constant.
So, first we need to get k. We are given that g(x) = 0.2 when x = 0.1
Substitute with these values to get k as follows:
g(x) = k/x
0.2 = k/0.1
k = 0.2*0.1 = 0.02
Now, the equation became:
g(x) = 0.02 / x
We need to get the g(x) when x = 1.6
Therefore, we will substitute with x in the equation and calculate the corresponding g as follows:
g(x) = 0.02 / 1.6
g(x) = 0.0125
