Okay so I'm going to set up a equation:
5.27= 3.40+ 0.85x, we have our total our price of one pineapple and our variable
next I isolate the variable:
5.27-3.40=0.85x
next:
1.87=0.85x
x= 2.2
she bought 2.2 pounds of tomatoes
Point Y is (6, -1)
Subtract 6 from the y coordinate in point y since it is translated down. keep the x coordinate since it is only being translated up and down, or by the y axis
Answer:
a
Step-by-step explanation:
because it is
A generic point on the graph of the curve has coordinates
The derivative gives us the slope of the tangent line at a given point:
Let k be a generic x-coordinate. The tangent line to the curve at this point will pass through 
and have slope 
So, we can write its equation using the point-slope formula: a line with slope m passing through 
has equation
In this case, 
and 
, so the equation becomes
We can rewrite the equation as follows:
We know that this function must give 0 when evaluated at x=0:
This equation has no real solution, so the problem looks impossible.
Answer:
1. ║u-z║= 5.66
2.║v-w║=6.0
3. ║w-u║=6.08
4.║v-u║=7.81
Step-by-step explanation:
The vectors are given as;
u = <-1, -3>, v = <5,-8>, w = <5, -2>, and z = <3, 1>.
To find the magnitude of the vectors;
1. ║u-z║
<-1 - 3> = <-4 and < -3 - 1> = <-4
║<-4,-4> ║= √{ -4²+-4²} = √32 = 5.66
2.║v-w║
<5,-8> - <5,-2>
<5-5> , <-8--2>
<0,-6>
║<0,-6>║= √{0²+ -6²} = √36 = 6
3. ║w-u║
<5,-2> - <-1,-3>
<5--1> , <-2--3>
<6,1>
║6,1║= √{6²+1²} = √36+1 = √37 = 6.08
4.║v-u║
<5,-8> - <-1,-3>
<5--1> , <-8--3>
< 6 , -5 >
║6,-5║= √{6²+-5²} = √36+25 =√61 = 7.81
