In
order to solve for a nth term in an arithmetic sequence, we use the formula
written as:<span>
an = a1 + (n-1)d
where an is the nth term, a1 is the first value
in the sequence, n is the term position and d is the common difference.
</span><span>THIRD
</span><span>A3=4+(3-1)(-5)
A3 = -6
A(3)=-2(3-1)(-5)
A3 = 20
</span><span>
FIFTH
</span>A5=4+(5-1)(-5)
A5 = -16
A(5)=-2(5-1)(-5)
A5 = 40<span>
TENTH
</span>A10=4+(10-1)(-5)
A10 = -41
A(10)=-2(10-1)(-5)
A10 = 90
Answer:
I think C and D options can be correct
Step-by-step explanation:
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1/7
Step-by-step explanation:
A neutral atom contains equal amount of proton and
electron.
A negative ion contains extra electrons hence there is
additional outer shell so it is expected that the radius is bigger than that of
a neutral atom.
While a positive ion contains less electron so there is
less outer shell so the radius is smaller than that of a neutral atom.
Arranging the radius in increasing order:
<span>positive ion, neutral atom, negative ion</span>
Answer:
Step-by-step explanation:
