To make foods such as bread, yoghurt and cheese.
They'll most likely cacth the skin fungus too. the towel may wipe off bacteria of the fungus and dead skin cells, and the other person using it may be wiping those bacteria and dead skin cells on them too.
The answer is negative controls. These are groups where no phenomenon is probable. They ensure that there is no effect when there should be no effect. Where there are only two possible outcomes, e.g. positive or negative, if the treatment group and the negative control both produce a negative result, it can be concluded that the treatment had no effect. If the negative control group and the treatment group both yield a positive result, it can be inferred that a puzzling variable is involved in the occurrence under study, and the positive results are not only due to the treatment. In other examples, outcomes might be measured as lengths, times, percentages, and so forth.
Answer:
b. cause an increase in blood pH.
Explanation:
Carbonic anhydrases are zinc-containing enzymes that catalyze the reversible reaction of conversion between CO2 and bicarbonates (carbon dioxide hydration and bicarbonate dehydration). The conversion of bicarbonate to CO2 facilitates its entry into the cell. On the other hand, the conversion of CO2 to bicarbonate helps keep the CO2 inside the cell.
This enzyme is important in all living organisms for maintenance of acid-base balance (regulates pH ). For example, carbonic anhydrases lowers pH in the stomach by producing an acid.
Answer:
The genotype of the F1 was wy+/w+y.
Explanation:
One of the given options has a typo: the red eye-brown body offspring count should be 56 instead of 561.
<u>We have two genes with two alleles each:</u>
Red eyes (w+) is dominant over white eyes (w).
Brown body (y+) is dominant over yellow body (y).
The phenotypes of the F2 tesulting from a test cross (F1 x wy/wy) are:
- wy+/ey (white-eye, brown body): 670
- w+y/wy (red-eye, yellow body): 650
- wy/wy (white-eye, yellow body): 38
- w+y+/wy (red-eye, brown body 56
If the genes w and y are linked, two phenotypes in the F2 will be much more abundant than the other two. Recombination during meiosis is a rare event, so the most abundant phenotypes are the parentals (the ones present in the F1 parent).
Every individual in the offpsring has a <em>wy</em> chromosome, as this was the gamete inherited from the test cross individual.
In this case, the most abundant gametes are wy+ and w+y, so the genotype of the F1 was wy+/w+y.
Notice how when recombination occurs in the F1 parent, the recombinant gametes appear: wy and w+y+, which are the less abundant in the F2 progeny.
