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puteri [66]
3 years ago
8

How much water would I need to add to 500 ml of a 2.4 M KCL solution to make a 1.0 M solution

Chemistry
1 answer:
Yuki888 [10]3 years ago
5 0

the answer is 700ml

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4. A 14.5-L balloon is in the air where it is 20.0 C at 0.980-atm. A wind passes over and the balloon's pressure becomes 740.0-m
jeka94

The temperature of the wind as that decreases the volume and the pressure of the balloon to the given values is 14.09°C.

<h3>What is Combined gas law?</h3>

Combined gas law put together both Boyle's Law, Charles's Law, and Gay-Lussac's Law. It states that "the ratio of the product of volume and pressure and the absolute temperature of a gas is equal to a constant.

It is expressed as;

P₁V₁/T₁ = P₂V₂/T₂

Given the data in the question;

  • Initial volume V₁ = 14.5L
  • Initial pressure P₁ = 0.980atm
  • Initial temperature T₁ = 20.0°C = 293.15K
  • Final volume V₂ = 14.3L
  • Final pressure P₂ = 740.mmHg = 0.973684atm
  • Final temperature T₂ = ?

We substitute our given values into the expression above.

P₁V₁/T₁ = P₂V₂/T₂

( 0.980atm × 14.5L )/293.15K = ( 0.973684atm × 14.3L )/T₂

14.21Latm / 293.15K = 13.92368Latm / T₂

14.21Latm × T₂ = 13.92368Latm × 293.15K

14.21Latm × T₂ = 4081.72679LatmK

T₂ = 4081.72679LatmK / 14.21Latm

T₂ = 287.24K

T₂ = 14.09°C

Therefore, the temperature of the wind as that decreases the volume and the pressure of the balloon to the given values is 14.09°C.

Learn more about the combined gas law here: brainly.com/question/25944795

#SPJ1

4 0
2 years ago
If you obtain 3.0 grams of aspirin from an experiment that could make no more than 3.14 grams, what is the percent yield?
Masteriza [31]

Answer:

96%

Explanation:

To find the percent yield, we can use this equation

\frac{Actual}{Theoretical} *100

The actual yield of aspirin is 3.0 and the theoretical is 3.14 in this case, so just plug the numbers in.

\frac{3.0}{3.14} *100\\\\ =96

Thus the percent yield is 96%

;)

3 0
3 years ago
New substances are produced by a(n)<br> change.
Orlov [11]

Answer:

New substances are produced by a chemical change

8 0
3 years ago
Read 2 more answers
How is the potential (voltage) of a redox reaction determined using the reduction
LuckyWell [14K]

Answer:

caused by the ability of electrons to flow from one half cell too the other

Explanation:

How is the potential voltage of a redox reaction?

The potential difference is caused by the ability of electrons to flow from one half cell to the other. Electrons are able to move between electrodes because the chemical reaction is a redox reaction. A redox reaction occurs when a certain substance is oxidized, while another is reduced.

6 0
3 years ago
CO
KonstantinChe [14]

Answer:

1) The number of the listed compounds that have ionic bonds between them are 5 compounds

2) Their formulas showing their charges within the compounds are;

NaCl ↔ Na⁺+Cl⁻

MgO ↔ Mg²⁺+O²⁻

K₂O ↔ 2K⁺+O²⁻

LiF ↔Li⁺+F⁻

CaO ↔ Ca⁺+O²⁻

3) The major reason they were selected is because they are compounds formed by the combination of a metal and a nonmetal

Explanation:

1) An ionic bond involves the transfer of an atoms valence to another atom, such that the ions formed by the ionic chemical bond will be oppositely charged

Therefore, metals, which are elements that mainly have a few electrons in their outermost shell, loses their valence electrons and become positively charged, while non metals, which require a few electrons to complete the stable octet electronic configuration, receive the electrons from the metallic atoms and become negatively charged

Therefore, the compounds formed between a metal and a nonmetal in the list are the the compounds containing ionic bonds, including

NaCl, MgO, K₂O, LiF, and CaO

Therefore, 5 compounds contain ionic bonds between them;

2) Their formulas are;

NaCl, MgO, K₂O, LiF, and CaO

3) The major reason that the chosen compounds contain ionic bonding between them is because they involve the combination of a metal and a nonmetal as follows;

a) NaCl → Na⁺ (metal ion) + Cl⁻(nonmetal ion)

b) MgO → Mg²⁺ (metal ion) + O²⁻(nonmetal ion)

c) K₂O → 2K⁺ (metal ion) + O²⁻(nonmetal ion)

d) LiF → Li⁺ (metal ion) + F⁻(nonmetal ion)

e) CaO → Ca⁺ (metal ion) + O²⁻(nonmetal ion)

6 0
3 years ago
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