1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Fantom [35]
3 years ago
13

Calculate the atomic mass of lead. The four lead isotopes have atomic masses and relative abundances of 203.973 amu (1.4%), 205.

974 amu (24.1%), 206.976 amu (22.1%) and 207.977 amu (52.4%).
Chemistry
1 answer:
blondinia [14]3 years ago
8 0
207.217 amu
Work:
203.973 amu *(0.014) = 2.855 amu
205.974 amu *(0.241) = 49.639 amu
206.976 amu *(0.221) = 45.741 amu
207.977 amu *(0.524) = 108.979 amu

2.855 + 49.639 + 45.741 + 108.979 = 207.217 amu
You might be interested in
A mixture of0.161 moles of C is reacted with 0.117 moles of O2 in a sealed, 10.0 L-vessel at 500.0 K, producing a mixture of CO
labwork [276]

Answer:

number of moles of CO2 is 0.054

number of moles of CO is 0.107

number of moles of O2 remaining is 0.01 mole

mole fraction of CO is 0.63

Explanation:

Firstly, we write the equation of reaction;

3C(s) +2O2(g) → CO2(g) +2CO(g)

Now, we proceed.

From the written equation, we can deduce that

3 mol C = 2 mol O2 = 1 mol CO2 = 2 mol CO

No of mol of C reacted = 0.161 mol

limiting reactant according to the question is Carbon

a. no of mol of CO2 formed = 0.161*1/3 = 0.054 moles ( no of moles of CO2 formed is one-third of no of moles of carbon reacted. This is obtainable from their mole ratio 1:3)

b. no of mol of CO formed = 0.161*2/3 = 0.107 mol

c. no of mol of O2 remaining = 0.117 - (0.151*2/3) = 0.117-0.107 = 0.01 mole

d. mole fraction of CO = no of mol of CO/Total number of moles

= 0.107/(0.107+0.054+0.01)

= 0.625730994152 which is approximately 0.63

5 0
3 years ago
Help me please and ty
satela [25.4K]

Answer:

it the same side with the other side you fellow the other side

Explanation:

7 0
3 years ago
Read 2 more answers
In which set of elements would all members be expected to have very similar chemical properties?
zepelin [54]

Answer:

each group of the periodic table.

example group 7 - fluorine, chlorine, bromine, iodine, astatine, tennessine

6 0
2 years ago
If I log out of Brainly and delete the Brainly app from my phone, will my account still be up and active?
Darya [45]
Yes and you can log in to it later as well
4 0
3 years ago
A cylindrical glass bottle 21.5 cm in length is filled with cooking oil of density 0.953 g/mL. If the mass of the oil needed to
jeka57 [31]

Answer:inner Diameter =9.19cm

Explanation:

Density is calculated as Mass/ Volume

therefore

Volume= Mass/ Density = 1360g/ 0.953g/ml=1,427 ml

1ml = 1cm³

1,427ml = 1,427cm³

Also We know that Volume of a cylinder = πr²h or  πr²l

1,427cm³ = 3.142 x r² x 21.5 cm

 r² =  1,427cm³/ (3.142 x 21.5cm)

r² =21.124cm²

\sqrt{21.124}= r²

r= 4.596cm

Diameter=  2 x radius

=2 x 4.596

=9.19cm

7 0
3 years ago
Other questions:
  • What does the chemical formula CaCI2 show about the compound or represents?
    12·1 answer
  • Which of the following is true about neutrons?
    6·1 answer
  • What two elements do not need eight valence electrons to stay stable?
    6·1 answer
  • Compare element factories to real factories
    6·1 answer
  • In the process of electrolysis current can flow through a liquid because
    13·2 answers
  • “Dry ice” is the solid form of carbon dioxide. Determine the number of mass of CO2 gas in grams that are present in 61.8 L of CO
    11·1 answer
  • Consider the two facts below:
    14·1 answer
  • Using the same sample of gas (P1 = 565 torr , T1 = 27 ∘C ), we wish to change the pressure to 5650 torr with no accompanying cha
    5·1 answer
  • Identify the steps that are followed in taking a stratified random sample. i. Take a sample of size n/k from each strata, where
    10·1 answer
  • Convert the following descriptions into balanced equations:
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!