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Lyrx [107]
3 years ago
12

What is the purpose of the following in the experiment of Synthesis of Methyl Salicylate

Chemistry
1 answer:
Aneli [31]3 years ago
7 0

Answer:

1. Phosphoric Acid : Catalyst

2. Methyl Anthranilate : Reactive

3. Sodium Nitrite : Reactive

4. Diethyl Ether : Solvent and reactant

5. Nitrogen : Sub-product

Explanation:

The phosphoric acid is used as a catalyst for the reaction, the methyl anthranilate will react with the sodium nitrite to produce methyl salicylate, along with the diethyl ether and the nitrogen is a sub-product of the reaction.

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Write any two differences between autotrophs and heterotrophs ​. subject-science
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Answer:

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Explanation:

Btw I searched this up found it on a website called byjus.com. Hope this helps!

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3 years ago
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How was island hopping a change in strategy for the us military?
Otrada [13]
Well, it was to capture Japanese controlled islands until the Japanese came into range of the American Bombers, which was different from them going after the Japanese and invading the islands.
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3 years ago
The bonds in the compound MgSO4 can be described as
Butoxors [25]
C. Sulfur and oxygen (non metals) forms a covalent bond while the magnesium (a metal) will react with both non metals to form an ionic bond
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4 years ago
Which element has a larger atomic radius than sulfur? chlorine cadmium fluorine oxygen
zhuklara [117]

Answer:

  • <u>Cadmium has larger atomic radius than sulfur.</u>

Explanation:

Down a period, atomic radii decrease from left to right due to the increase in the number of protons and electrons across a period: when a proton is added the pull of the electrons towards the nucleus is larger, so the size of the atom decreases.

Hence, you can compare the elements that belong to a same period and predict that the atom with lower atomic number (number of protons) will haver larger atomic radius. With that:

  • Oxygen and fluorine are in the period 3, being oxygen to the left of fluorine, so oxygen is larger than fluorine.

  • Sulfur and chlorine are in the period 4, being sulfur to the left of chlorine, so sulfur is larger than chlorine.

Now see whan happens down a group. Atomic radius increases from top to bottom within a group due to electron shielding. That permits you to compare the size of the elements in a group:

  • Fluorine and chlorine are in the same group (17), with chlorine directly below fluorine, so the atomic radius of chlorine is larger than the atomic radius of fluorine.

  • Sulfur and oxygen are in the same group (16), with sulfur directlly below oxygen, so sulfur the atomic radius of sulfur is larger than the atocmi radius of oxygen.

So far, you can rank the atomic radius of sulfur, chlorine, fluorine, and oxygen, in increasing order as:

  • O < F < Cl < S, concluding that O, F, and Cl have smaller atomic radius than S.

Cadmiun, Cd, is to the left and below sulfur, so both electron shielding (down a group) and increase of the number of protons (down a period) lead to predict the cadmium has a larger atomic radius than sulfur.

8 0
3 years ago
PLZ HELP I WILL GIVE BRAINLISTS TO RIGHT ANSWER
galina1969 [7]
..........The answer is B
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