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4vir4ik [10]
2 years ago
7

Find the measure of the three missing angles in the parallelogram below.

Mathematics
2 answers:
Leya [2.2K]2 years ago
7 0

According to definition of parallelogram

  • Consecutive angles of a parallelogram have sum 180°
  • Opposite angles are equal
  • Opposite sides are equal

\\ \rm\hookrightarrow z=103

  • x+103=180
  • x=77°

And

  • y=x=77
elixir [45]2 years ago
4 0

Answer: x = 77 degrees, y = 77 degrees, z = 103 degrees

Step-by-step explanation:

Since y and 103 are essentially same side interior angles, they must add up to 180. Therefore, y = 180-103 = 77 degrees.

Opposite angles of a paralellogram are equal.

Therefore, x = y = 77 degrees and z = 103 degrees

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I don't know if this answer is right but I think it would be 52
4 0
3 years ago
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There are three consecutive integers. The sum of the first two is 51 more than the third. Find the integers.
Sauron [17]

Answer:

52,53,54

Step-by-step explanation:

x, x+1, x+2

2x+1=x+53

x+1=53

x=52

x+1=53

x+2=54

3 0
3 years ago
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likoan [24]
She is wrong she should have added 18 to both sides
7 0
2 years ago
Find the equation of the inverse.<img src="https://tex.z-dn.net/?f=y%20%3D%20%20%7B2%7D%5E%7Bx%20%2B%205%7D%20%20-%206" id="TexF
Contact [7]

Find the equation of the inverse.

y =  {2}^{x + 5}  - 6

we have

y=\mleft\{2\mright\}^{\mleft\{x+5\mright\}}-6

step 1

Exchange the variables

x for y and y for x

x=\{2\}^{\{y+5\}}-6

step 2

Isolate the variable y

(x+6)=2^{(y+5)}

apply log both sides

\begin{gathered} \log (x+6)=(y+5)\cdot\log (2) \\ y+5=\frac{\log (x+6)}{\log (2)} \\  \\ y=\frac{\log(x+6)}{\log(2)}-5 \end{gathered}

step 3

Let

f^{(-1)}(x)=y

therefore

the inverse function is

f^{(-1)}(x)=\frac{\log(x+6)}{\log(2)}-5

7 0
1 year ago
Birth weights of babies born to full-term pregnancies follow roughly a Normal distribution. At Meadowbrook Hospital, the mean we
Marina86 [1]

Answer:

Required Probability = 0.1283 .

Step-by-step explanation:

We are given that at Meadow brook Hospital, the mean weight of babies born to full-term pregnancies is 7 lbs with a standard deviation of 14 oz.

Firstly, standard deviation in lbs = 14 ÷ 16 = 0.875 lbs.

Also, Birth weights of babies born to full-term pregnancies follow roughly a Normal distribution.

Let X = mean weight of the babies, so X ~ N(\mu = 7 lbs , \sigma^{2}  = 0.875^{2}  lbs)

The standard normal z distribution is given by;

              Z = \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, X bar = sample mean weight

             n = sample size = 4

Now, probability that the average weight of the four babies will be more than 7.5 lbs = P(X bar > 7.5 lbs)

P(X bar > 7.5) = P( \frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } } > \frac{7.5-7}{\frac{0.875}{\sqrt{4} } }  ) = P(Z > 1.1428) = 0.1283 (using z% table)

Therefore, the probability that the average weight of the four babies will be more than 7.5 lbs is 0.1283 .

8 0
3 years ago
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