The triangles ABC and EDF are congruent, meaning they have the same side lengths and angles measures.
The measure of DF, as both triangles are congruent, is equal to the measure of BC.
We can calculate the length of BC using the distance formula:
![\begin{gathered} D=\sqrt[]{(x_c-x_b)^2+(y_c-y_b_{})^2} \\ D=\sqrt[]{(2-2)^2+(-1-4)^2} \\ D=\sqrt[]{0^2+(-5)^2} \\ D=\sqrt[]{(-5)^2} \\ D=|-5| \\ D=5 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20D%3D%5Csqrt%5B%5D%7B%28x_c-x_b%29%5E2%2B%28y_c-y_b_%7B%7D%29%5E2%7D%20%5C%5C%20D%3D%5Csqrt%5B%5D%7B%282-2%29%5E2%2B%28-1-4%29%5E2%7D%20%5C%5C%20D%3D%5Csqrt%5B%5D%7B0%5E2%2B%28-5%29%5E2%7D%20%5C%5C%20D%3D%5Csqrt%5B%5D%7B%28-5%29%5E2%7D%20%5C%5C%20D%3D%7C-5%7C%20%5C%5C%20D%3D5%20%5Cend%7Bgathered%7D)
As BC is congruent with DF and BC=5, the length of DF is 5 units.
Answer:
the fraction can be write as 7/8
3/4=6/8
6/8+1/8=7/8
Step-by-step explanation:
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Answer: 
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all the details are in the attachment.
Answer:
4 in.
Step-by-step explanation:
length times width = area
actually im not really sure lol. we havent done this in a while
