Answer:
decreasing at 390 miles per hour
Step-by-step explanation:
Airplane A's distance in miles to the airport can be written as ...
a = 30 -250t . . . . . where t is in hours
Likewise, airplane B's distance to the airport can be written as ...
b = 40 -300t
The distance (d) between the airplanes can be found using the Pythagorean theorem:
d^2 = a^2 + b^2
Differentiating with respect to time, we have ...
2d·d' = 2a·a' +2b·b'
d' = (a·a' +b·b')/d
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To find a numerical value of this, we need to find the values of its variables at t=0.
a = 30 -250·0 = 30
a' = -250
b = 40 -300·0 = 40
b' = -300
d = √(a²+b²) = √(900+1600) = 50
Then ...
d' = (30(-250) +40(-300))/50 = -19500/50 = -390
The distance between the airplanes is decreasing at 390 miles per hour.
Answer:
{a , c}
Step-by-step explanation:
first find u intersection p
n(U n P ) = {a , b , c , d} n {b , d , e}
={d , b}
intersection means element or values which lies in both the sets
now to find p complement
note : p( bar at the top ) is read as p complement
p complement = n(U) - n(U n P)
={a , b , c , d} - {d , b}
={a , c}
n(U) -n(U n P) means the elements which is only in n(U ) but not in n(U n P)
20 kg remaining in bag 1.
40 kg remaining in bag 2.
Answer:
what graph?
Step-by-step explanation:
What’s in it for me will u give me vbucks
