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11Alexandr11 [23.1K]
2 years ago
15

Help

Mathematics
1 answer:
Airida [17]2 years ago
8 0

Step-by-step explanation:

Everytime the dice is rolled, there is a 50% chance to get an odd number.

Hence 50% * 50% = 25%.

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Match each verbal description to its corresponding expression.
Aliun [14]
I need points thank you
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3 years ago
You have to find the domain and range
Dahasolnce [82]

Answer:

First off, we look for which circles are open or closed.

We start with an open interval since the circle on the left is open and end with a closed interval since the circle on the right is closed.

Domain is all x values, Range is all y values

The graph shows the continous function going from -3 to 1 on the x axis.

According to the circles, this means our domain will be (-3,1].

Now, the range doesn't care about if its closed or not. So we can say the graph is on the y axis from -4 and 0. This means the range is -4<y<0

I used different notations for both just incase you need to represent your answer differently :)

-3<x<1 & (-3,1] . Range is [-4,0]. 0>y>-4 looks correct as-well.

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2 years ago
A company rents water tanks shaped like cylinders. Each tank has a radius of 6 feet and a height of 2 feet. The cost is $3 per c
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7 0
3 years ago
How to solve these question?
mart [117]
3.) An extreme value refers to a point on the graph that is possibly a maximum or minimum. At these points, the instantaneous rate of change (slope) of the  graph is 0 because the line tangent to the point is horizontal. We can find the rate of change  by taking the derivative of the function.

y' = 2ax + b

Now that we where the derivative, we can set it equal to 0.

2ax + b = 0

We also know that at the extreme value, x = -1/2. We can plug that in as well.

2a (-\frac{1}{2} ) + b = 0

The 2 and one-half cancel each other out.

-a + b = 0

a = b

Now we know that a and b are the same number, and that ax^2 + bx + 10 = 0 at x = -1/2. So let's plug -1/2 in for x in the original function, and solve for a/b.

a(-0.5)^2 + a(-0.5) + 10 = 0

0.25a - 0.5a + 10 = 0

-0.25a = -10

a = 40

b = 40

To determine if the extrema is a minima or maxima, we need to go back to the derivative and plug in a/b.

80x + 40

Our critical number is x = -1/2. We need to plug a number that is less than -1/2  and a number that is greater than -1/2 into the derivative.

LESS THAN:
80(-1) + 40 =  -40

GREATER THAN:
80(0) + 40 = 40

The rate of change of the graph changes from negative  to positive at x = -1/2, therefore the extreme value is a minimum.

4.) If the quadratic function is symmetrical about x = 3, that means that the minimum or maximum must be at x = 3.

y' = 2ax + 1

2a(3) + 1 = 0

6a = -1

a = -1/6

So now plug the a value and x=3 into the original function to find the extreme value.

(-1/6)(3)^2 + 3 + 3 = 4.5

The extreme value is 4.5


7 0
3 years ago
Can someone pls help me ASAP I’ll give brainiest
Umnica [9.8K]
3^x+1=3^3
X+1=3
X=3-1
X=2
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2 years ago
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