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Len [333]
2 years ago
12

Answer question in image attached :) 20 points

Mathematics
2 answers:
8090 [49]2 years ago
8 0

Answer:

AC = 3(tan 50°)

Step-by-step explanation:

Trig ratios:

sin(\theta)=\dfrac{O}{H} \ \ \ \ cos(\theta)=\dfrac{A}{H} \ \ \ \ tan(\theta)=\dfrac{O}{A}

where \theta is the angle, O is the side opposite the angle, A is the side adjacent to the angle and H is the hypotenuse of a right triangle

Given:

  • Angle = 50°
  • A = 3 in
  • O = AC

Therefore, use the tan ratio:

\implies tan(50)=\dfrac{AC}{3}\\\\\implies AC=3tan(50)\\\\

REY [17]2 years ago
6 0

Answer:

3(tan 50°)

Step-by-step explanation:

AC is the height

=> tan50 = AC/3

=>  AC = 3(tan 50°)

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I need help using the distance formula to find the perimeter of a parallelogram JKLM
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so let's just find say... KL and  her twin will be the same.


\bf ~~~~~~~~~~~~\textit{distance between 2 points}&#10;\\\\&#10;K(\stackrel{x_1}{-0.5}~,~\stackrel{y_1}{-1.7})\qquad&#10;L(\stackrel{x_2}{-0.7}~,~\stackrel{y_2}{-0.4})~\hspace{3.5em}&#10;d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}


\bf KL=\sqrt{[-0.7-(-0.5)]^2+[-0.4-(-1.7)]^2}&#10;\\\\\\&#10;KL=\sqrt{(-0.7+0.5)^2+(-0.4+1.7)^2}\implies KL=\sqrt{(-0.2)^2+1.3^2}&#10;\\\\\\&#10;KL=\sqrt{0.04+1.69}\implies KL=\sqrt{1.73}\implies KL\approx 1.315&#10;\\\\[-0.35em]&#10;\rule{34em}{0.25pt}\\\\&#10;\stackrel{\textit{perimeter}}{\stackrel{LM}{1.2}+\stackrel{KJ}{1.2}+\stackrel{KL}{1.315}+\stackrel{JM}{1.315}}\implies 5.03

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3 years ago
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