Answer:
C.
perpendicular lines intersect in at least two points..
ok im not sure sorry
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Answer:
we know that, Volume of cube=a³
Let volume of 1st cube be 2x with side a and other be x with side A (according to given ratio)
Step-by-step explanation:
ATQ: 2x=a³ and, x=A³
a=³√2x and, A=x
we know that, surface area of cube is 6a²
Thus, surface area of 1st cube = 6(³√2x)²
= 6³√4x²
Surface area of 2nd cube=6(x)²=6x²
Ratio of S.A=(6³√4x²)÷(6x²)
Ratio of S.A=³√4:1
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Given that the First term of the Arithmetic sequence = -3
⇒ a = -3
We know that nth term of a Arithmetic sequence is : Tn = a + (n - 1)d
where a is the first term and d is the common difference
Given that 10th term is 15
⇒ T₁₀ = -3 + (10 - 1)d
⇒ -3 + (10 - 1)d = 15
⇒ 9d = 18
⇒ d = 2
⇒ Common difference of given Arithmetic Sequence is 2
C. Got you man.
Lemme know if I’m right
