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ANTONII [103]
2 years ago
15

Which of the following WOULD NOT affect the level at which a cargo ship floats

Chemistry
1 answer:
kow [346]2 years ago
3 0
Answer: D. The depth of the water does not affect the level at which a cargo ship floats.
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The rate constant for a reaction is 4.65 L mol-1s-1. What is the overall order of the reaction? zero
il63 [147K]

Answer:

second order

Explanation:

units of reaction and their order.

Zero order --> M^1 s^-1 = M/s

First order --> M^0 s^-1 = 1/s

Second order --> M^-1 s^-1 = L/mol s

In the question rate constant k =  4.65 L mol-1s-1. = 4.65 L/mol s

Hence, the reaction is a second order reaction

8 0
2 years ago
Read 2 more answers
Calculate the mass in grams, in 2.28 mol of H2SO4. Please show your work to receive credit.
solmaris [256]

Answer:

98g

Explanation:

h=1*2=2

s=32

0=16*4=64

64+32+2=98

4 0
3 years ago
Two liquids, a and b are immiscible. liquid a has a density of 0.89 g/ml. liquid b has a density of 0.72 g/ml. what would you ex
Burka [1]
In the given above, we have two densities which are 0.89 g/mL and 0.72 g/mL. We are also given that the liquids are immiscible. After the settlement of the liquids, they will form two layers.

The heavier substance, the one which has a higher density will be at the bottom and the lighter substance, the one which has a lower density will be at the top layer.
5 0
3 years ago
The isomerization of methylisonitrile to acetonitrileCH3NC(g)→CH3CN(g)is first order in CH3NC . The rate constant for the reacti
lisabon 2012 [21]

Answer:

Option E, Half life = 2.96\times 10^3\ s

Explanation:

For a first order reaction, rate constant and half-life is related as:

            t_{1/2}=\frac{0.693}{k}

Where,

t_{1/2} = Half life

k = Rate constant

Rate constant given = 2.34\times 10^{-4}\ s^{-1}

t_{1/2}=\frac{0.693}{k}

=\frac{0.693}{2.34 \times 10^{-4}}=2.96\times 10^3\ s

So, the correct option is option E.

4 0
3 years ago
I’ll give the brainliest to whoever gets it right!!!
kramer

Answer:

itll slowly decay

Explanation:

i hope this helps

8 0
3 years ago
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