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Lynna [10]
3 years ago
9

In an isolated system, two copper bars at different temperatures transfer energy until both are at the same temperature. How wou

ld the transfer of energy be different if the bars were in an open system?
A. Energy transfer would occur only between the copper bars.

B. Energy transfer would occur between the copper bars and the surroundings.

C. No energy transfer would occur between the copper bars or the surroundings.

D. Energy transfer would occur only with the surroundin
Chemistry
1 answer:
ella [17]3 years ago
4 0

Answer is: B. Energy transfer would occur between the copper bars and the surroundings.

Closed system is a physical system that does not allow transfer of mass and energy in or out of the system.

Open system is a physical system that does allow transfer of mass and energy in or out of the system, have input and output flows.

Thermal conductuction is the transfer of heat through physical contact. Thermal conduction is the transfer of heat by microscopic collisions of particles.

Heat spontaneously flows from a hotter to a colder body.

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Name two factors that influence the viscosity of a lava flow
mr_godi [17]
Three factors that affect magma viscosity are temperature, composition, and presence of dissolved gases. 
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3 years ago
A substance that cannot be chemically broken down into simpler substances is a an electron. b a heterogeneous mixture. c an elem
antiseptic1488 [7]

Answer:

c. an element.

Explanation:

An element -

It refers to the substance , which has same type of atoms , with exactly same number of protons , is referred to as an element .

In term of chemical species , elements are the smallest one , and can not be bifurcated down to any further small substance by the means of any chemical reaction .

Hence , from the given information of the question ,

The correct term is an element  .

3 0
3 years ago
Please answer 15 POINTS !!!
insens350 [35]

Answer:

6 C O 2 + 6 H 2 O + Δ → C 6 H 12 O 6 + 6 O 2

Explanation:

The  Δ  symbol denotes added energy, here in the form of sunlight. Strong  C = O , and  O − H  bonds have been broken, and this bond cleavage is only partially energetically compensated by the formation of  C − H  and  O = O  bonds. Hence the reaction is endothermic (energy input on LHS). Note that the reaction is balanced with respect to mass and charge (says he, checking to see whether it is indeed balanced!).

6 0
4 years ago
Determine the Eo for a Cu-Pb Voltaic Cell
blagie [28]

Answer:

The standard cell potential (E₀) for a Cu-Pb voltaic cell is +0.215V

The experiment is used to determine the standard electrode potential of the Cu-Pb Voltaic cell.

Explanation:

A Voltaic cell is one in which electric energy is produced as a result of the difference in electric potential between two electrodes in chemical solutions that are usually connected by a salt bridge.  

In a voltaic cell, the anode electrode is where oxidation (loss of electrons) occurs while reduction (gain of electrons) occurs at the cathode electrode.

The standard cell potential (E₀) is the difference between the potential of the cathode and anode at standard conditions, that is, at standard temperature, pressure and concentration.  

It is usually expressed as

E₀ = E₀cell (cathode) - E₀cell (anode)

From the given question, the half cell equations are :

Cu(s) - 2e ⇒ Cu²⁺. with  oxidation reaction occuring at the anode  

Pb²⁺  + 2e ⇒ Pb (s).  with reduction reaction occuring at the cathode

Meaning that the solid copper electrode is oxidised by losing two electrons which are gained by the Pb²⁺ ions which are subsequently reduced to solid lead at the other electrode.  

Each half cell reaction has a standard electric potential  (recall that the standard electric potential is the potential at standard conditions, that is, at standard temperature, pressure and concentrations.

)

The overall voltaic cell equation is given as:

Cu(s) I Cu²⁺(aq) II Pb²⁺ (aq) I Pb(s)

The standard cell potential E₀ is obtained by

:

E₀ = E₀cell (cathode) - E₀cell (anode)

At standard conditions, E₀ (Cu(s) ⇒ Cu²⁺  + 2e)  = - 0.340V

                       E₀ (Pb²⁺ + 2e ⇒ Pb(s) = - 0.125V

Therefore, the standard cell potential for a Cu-Pb voltaic cell is,

E₀ = -0.125V - (-0.340V)

  = -0.125V + 0.340V

  = +0.215V

4 0
3 years ago
How many valence electrons are there is the molecule CH 06P2
V125BC [204]
There are 32 :) hope is helps
8 0
3 years ago
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