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3 years ago

Answer correctly please !!!!!!!!!!!!!!! Will mark brainliest !!!!!!!!!!!!!!!!!

Chemistry

2 answers:

vichka [17]3 years ago

8 0

The picture is showing us how when you put a cold ice cube in a hot cup of water vapor comes out.

jolli1 [7]3 years ago

4 0

The ice cube i think is really cold

You might be interested in

How is stoichiometry used to calculate amount of product from amount of reactant?

Nadusha1986 [10]

Answer:

D. The coefficients give the ratio of mole reactant to moles product.

Explanation:

In stoichiometric calculations, the amount of product formed from reactants can be determined.

Using this approach, the number of moles of reactants and products on both sides of the expression must be balanced.
As a rule of thumb, the coefficients give the ratio of moles of reactants to moles of products.
This is very useful in a number of calculations using the stoichiometric approach.

5 0

3 years ago

El agua salubre es aquella que tiene más sales disueltas que el agua dulce. En el análisis de una muestra de aguas se encontró q

Slav-nsk [51]

Answer:

0.39 % m/m; 0.42 % m/v; 0.18 % v/v; 4200 ppm; 0.044 mol·L⁻¹; 0.041 mol/kg;

0.089 equiv/L; 0.000 74; 0.999 26

Explanation

Data:

Mass of MgCl₂ = 3.8 g

Volume of solution = 900 mL

Density of solution = 1.09 g/mL

Density of MgCl₂ = 2.32 g/cm³

Calculations

1. Percent m/m

$\text{Mass percent} = \dfrac{\text{Mass of component}}{\text{Total mass}} \times 100 \, \%\\\\\text{Total mass} = \text{900 mL} \times \dfrac{\text{1.09 g}}{\text{1 mL}} = \text{981 g}\\\\\text{Mass percent} = \dfrac{\text{3.8 g}}{\text{981 g}} \times 100 \,\% = \textbf{0.39 \% m/m}$

2. Percent m/v

$\text{Mass-by-volume percent} = \dfrac{\text{Mass of component}}{\text{Total volume}} \times 100 \, \%\\\\\text{ Mass-by-volume percent } = \dfrac{\text{3.8 g}}{\text{900 mL}} \times 100 \,\% = \textbf{0.42 \% m/v}$

3. Percent v/v

$\text{Volume percent} = \dfrac{\text{Volume of component}}{\text{Total volume}} \times 100 \, \%\\\\\text{Volume of MgCl}_{2} = \text{3.8 g} \times \dfrac{\text{1 mL}}{\text{2.32 g}} = \text{1.64 mL}\\\\\text{ Mass-by-volume percent } = \dfrac{\text{1.64 mL}}{\text{900 mL}} \times 100 \,\% = \textbf{0.18 \% v/v}$

4. Parts per million

$\text{Ppm} = \dfrac{\text{milligrams of solute}}{\text{litres of solution}} = \dfrac{\text{3800 mg}}{\text{0.900 L}} = \textbf{ 4200 ppm}$

5. Molar concentration

$\text{Molar concentration} = \dfrac{\text{moles of solute}}{\text{litres of solution}}\\\\\text{Moles of MgCl}_{2} = \text{3.8 g} \times \dfrac{\text{1 mol}}{\text{95.21 g}} = \text{0.040 mol}\\\\\text{Molar concentration} = \dfrac{\text{0.040 mol}}{\text{0.900 L}} = \textbf{0.044 mol/L}$

6. Molal concentration

$\text{Molal concentration} = \dfrac{\text{moles of solute}}{\text{kilograms of solvent}}$

Mass of water = Mass of solution - mass of solute = 981 g - 3.8 g = 977 g = 0.977 kg

$\text{Molar concentration} = \dfrac{\text{0.040 mol}}{\text{0.977 kg}} = \textbf{0.041 mol/kg}$

7. Normality

The normality is the number of equivalents per litre of solution.

The normality of an ion equals the molar concentration times the charge on the ion.

Thus, the normality of MgCl₂ is twice the molar concentration.

Normality = 2 × 0.044 mol·L⁻¹ = 0.089 equiv·L⁻¹

8. Mole fraction of solute

$\chi_{\text{solute}} = \dfrac{n_{\text{solute}}}{n_{\text{total}}}$

Moles of MgCl₂ = 0.040 mol

$\text{Moles of water} = \text{977 g} \times \dfrac{\text{1 mol}}{\text{18.02 g}} = \text{54.23 mol}$

Total moles = n₂ + n₁ = 0.040 mol + 54.23 mol = 54.27 mol

$\chi_{2} = \dfrac{\text{0.040 mol}}{\text{54.23 mol}} = \mathbf{0.00074}$

9. Mole fraction of solvent

χ₁ = 1 - χ₂ = 1 - 0.000 74 = 0.999 26

4 0

3 years ago

The specific heat of a substance is the amount of energy needed to raise the temperature of:.

sesenic [268]

the specific heat capacity is the energy needed to raise the temperature of 1kg of that substance by 1 degree

4 0

3 years ago

If the balloon had a volume of 3 L at a depth of 50 m, what was the original volume of the balloon it we assume the pressure at

disa [49]

If the balloon had a volume of 3 L at a depth of 50 m, the original volume of the balloon will be

<h3 /><h3>What is Significant figures ?</h3>

Significant figures are the number of digits in a value, often a measurement, that contribute to the degree of accuracy of the value.

The pressure at a depth of 40 m is the hydrostatic pressure of the water plus the atmospheric pressure.

The hydrostatic pressure P of a liquid is given by the formula ;

P = ρgh

where,

ρ = the density of the liquid (Density of water = 1000 kg m⁻³)
g = the acceleration due to gravity (9.81 ms⁻²)
h = the depth of the liquid (Given : 50 m)

P = 1000 kg m⁻³ x 9.81 ms⁻² x 50 m

= 1000 kg m⁻¹ x 9.81 s⁻² x 50

= 4.9 x 10⁵ Pa

Lets's Convert Pa in to atm

= 4.9 x 10⁵ Pa x 1 / 103. 325 x 10³ Pa

= 4.7 atm

Mow, lets calculate P(atm) ;

P(atm) = 14.7 psi x 1 atm / 14.7 psi

= 1 atm

Total Pressure at 50 m is ;

P(total) = 4.7 atm + 1 atm

= 5.7 atm

Now we can apply Boyle's Law to calculate the volume of the balloon at the surface.

P₁V₁ = P₂V₂

V₂ = P₁V₁ / P₂

According to the question ;

P₁ = 5.7 atm
P₂ = 1 atm
V₁ = 3 L
V₂ = ?

V₂ = 3 L x 5.7 atm / 1 atm

= 17.1 L

= 20 L ( 1 significant figure)

Learn more about Boyles law here ;

brainly.com/question/1437490

#SPJ1

8 0

2 years ago

What is the Ground state electron configuration for lead?

notsponge [240]

Answer:

Lead atoms have 82 electrons and the shell structure is 2.8. 18.32. 18.4.

Explanation:

The ground state electron configuration of ground state gaseous neutral lead is [Xe].

3 0

4 years ago