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DedPeter [7]
3 years ago
14

What else would need to be congruent to show that ABC= AXYZ by ASA?

Mathematics
1 answer:
Agata [3.3K]3 years ago
7 0

Step-by-step explanation:

ASA stand for "angle-side-angle".

this means 2 angles have to be congruent, and then the side between these 2 angles.

the side(s) between the 2 given angles are AC and XZ.

so, these 2 sides need to be congruent too.

therefore B is the correct answer option.

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In a school one-third of all 240 students play soccer. Forty four students play both soccer and basketball and sixty students do
stiv31 [10]

Answer:

100 students play only basketball.            

Step-by-step explanation:

We are given the following information in the question:

Total number of students in school = 240

Number of students that play soccer =

\dfrac{1}{3}\times \text{Total number of students}\\\\=\dfrac{1}{3}\times 240 = 80

n(S) =80

n(S\cap B) = 44

n(S'\cap B') = 60

Formula:

n(S\cup B) = \text{Total} - n(S' \cap B')\\n(S\cup B) = n(S) + n(B) - n(S\cap B)

Putting the values, we get,

n(S\cup B) =240-60=180\\n(S\cup B) = 180 = 80 - 44 + n(B)\\n(B) = 180 - 80 + 44= 144

Thus, 144 students play  basketball.

Out of these 144, 44 plays soccer as well.

\text{Student only playing basketball} = 144 -44 = 100

Thus, 100 students play only basketball and not soccer.

7 0
4 years ago
IT'S FINALS TIME- PLEASE HELP
monitta

Answer:

It is 42 degrees! Hope this helps!

Step-by-step explanation:

7 0
3 years ago
Can someone please help me?
Molodets [167]

Answer: (2.3)

Step-by-step explanation:

8 0
3 years ago
14 ounces of olive oil for $3.59
Kamila [148]
25. 6 cents for each ounce
5 0
4 years ago
Suppose Pr(A)=0.25 and Pr(B)=0.48, where A and B are mutually exclusive. Find Pr(A ? B).
Slav-nsk [51]

Answer:  The required value is P(A ∪ B) = 0.73.

Step-by-step explanation:  Given that A and B are two mutually exclusive events where

P(A)=0.25~~~\textup{and}~~~P(B)=0.48

We are to find the following probability :

P(A ∪ B).

We know that

the intersection of two mutually exclusive events is null event. That is,

A ∩ B = ∅     ⇒  P(A ∩ B) = 0.

From the laws of probability, we have

P(A\cup B)=P(A)+P(B)-P(A\cap B)=0.25+0.48-0=0.73

Thus, the required value is P(A ∪ B) = 0.73.

4 0
4 years ago
Read 2 more answers
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