You take it like this=
8
-3
~~
3
+
3
+
3
-
1
~~
(4×2)
-
3
~~
[[5]]
《5+8》
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| 13 |
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Answer:
the correct answer would be b)8.2
Step-by-step explanation:
Answer:
bottom side (a) = 3.36 ft
lateral side (b) = 4.68 ft
Step-by-step explanation:
We have to maximize the area of the window, subject to a constraint in the perimeter of the window.
If we defined a as the bottom side, and b as the lateral side, we have the area defined as:

The restriction is that the perimeter have to be 12 ft at most:

We can express b in function of a as:

Then, the area become:

To maximize the area, we derive and equal to zero:

Then, b is:

Using the z-distribution, it is found that the lower limit of the 95% confidence interval is of $99,002.
<h3>What is a z-distribution confidence interval?</h3>
The confidence interval is:

In which:
is the sample mean.
is the standard deviation for the population.
In this problem, we have a 95% confidence level, hence
, z is the value of Z that has a p-value of
, so the critical value is z = 1.96.
The other parameters are given as follows:

Hence, the lower bound of the interval is:

The lower limit of the 95% confidence interval is of $99,002.
More can be learned about the z-distribution at brainly.com/question/25890103
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