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2 years ago

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If 3.06 grams of ammonia (NH₃) react with 0.0350 moles of chromium (III) nitrate as noted by the following equation, what is the

value of the fraction formed by ammonia? Cr(NO₃)₃ + NH₃ --> Cr(NH₃)₆(NO₃)₃

1 answer:

Lady bird [3.3K]2 years ago

3 0

What is the answer to this question

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A closed, frictionless piston-cylinder contains a gas mixture with the following composition on a mass basis: 40% carbon dioxide

Hitman42 [59]

Answer:

W=-37.6kJ, therefore, work is done on the system.

Explanation:

Hello,

In this case, the first step is to compute the moles of each gas present in the given mixture, by using the total mixture weight the mass compositions and their molar masses:

$n_{CO_2}=0.8kg*0.4*\frac{1kmolCO_2}{44kgCO_2}= 0.00727kmolCO_2\\\\n_{O_2}=0.8kg*0.25*\frac{1kmolO_2}{32kgO_2}=0.00625kmolO_2\\ \\n_{Ne}=0.8kg*0.35*\frac{1kmolNe}{20.2kgNe}=0.0139kmolNe$

Next, the total moles:

$n_T=0.00727kmol+0.00625kmol+0.0139kmol=0.02742kmol$

After that, since the process is isobaric, we can compute the work as:

$W=P(V_2-V_1)$

Therefore, we need to compute both the initial and final volumes which are at 260 °C and 95 °C respectively for the same moles and pressure (isobaric closed system)

$V_1=\frac{n_TRT_1}{P}= \frac{0.02742kmol*8.314\frac{kPa*m^3}{kmol\times K}*(260+273)K}{450kPa}=0.27m^3\\ \\V_2=\frac{n_TRT_2}{P}= \frac{0.02742kmol*8.314\frac{kPa*m^3}{kmol\times K}*(95+273)K}{450kPa}=0.19m^3$

Thereby, the magnitude and direction of work turn out:

$W=450kPa(0.19m^3-0.27m^3)\\\\W=-37.6kJ$

Thus, we conclude that since it is negative, work is done on the system (first law of thermodynamics).

Regards.

7 0

3 years ago

if I have 22.1 grams of CO2 gas at -188 degrees Celsius and 165 ml what is the pressure of the gas in kPa

Harman [31]

Answer:

P = 2.145kPa

Explanation:

Mass = 22.1g

Molar mass of CO2 = 44g/mol

Vol = 165mL = 0.165L

T = -188°C = (-188 + 273.15)K = 85.15K

R = 8.314J/mol.K

From ideal gas equation,

PV = nRT

P = pressure of the ideal gas

V = volume the gas occupies

n = number of moles if the gas

R = ideal gas constant

T = temperature of the gas

n = number of moles

n = mass / molar mass

n = 22.1 / 44 = 0.50moles

PV = nRT

P = nRT/ V

P = (0.5 × 8.314 × 85.15) / 0.165

P = 2145.26Pa = 2.145kPa

Pressure of the gas is 2.145kPa

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3 years ago

Which type of bond makes it possible for a macromolecule to interact with great specificity with just one out of the many thousa

Andrei [34K]

Answer:Non-covalent bonds

Explanation:

The Non-covalent bonds are bonds such as van der Waals forces of attraction, the Hydrogen bonds, hydrophobic bonds and so on. The Non-covalent bonds are very important types of bonding in large biological molecules.

Just like the question says, the Non-covalent bonds, ''makes it possible for a macromolecule to interact with great specificity with just one out of the many thousands of different molecules present inside a cell".

Ionic bonding is also a Non-covalent bonding. They(Non-covalent bonds) helps in the stability of large macromolecules.

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2 years ago

Lab report calorimetry and specific heat <br> HELP PLZ

dolphi86 [110]

Explanation:

Specific heat capacity can be calculated using the following equation: q = mc∆T In the equation q represents the amount of heat energy gained or lost (in joules ), m is the mass of the substance (in grams), c is the specific heat capacity of the substance (in J/g °C), and ∆T is the temperature change of the substance

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2 years ago

PLZ HELP IT BEING TIMED!!!!!! PLZ ANSWER!!!!!

Wittaler [7]

Answer:

YIKES. a bit late. Answers include 1, 2, 3

Explanation:

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2 years ago