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3 years ago

Will magnesium and fluorine atoms most likely form an ionic bond or a covalent bond?

Chemistry

2 answers:

Andreas93 [3]3 years ago

6 0

Answer:

Ionic bond

Explanation:

The magnesium atom gives up 2 electrons to form a magnesium ion, Mg2+ . The two electrons are transferred to fluorine atoms to form two fluoride ions, F–.

yan [13]3 years ago

4 0

Explanation:

Atomic number of magnesium is 12 and its electronic configuration is $1s^{2}2s^{2}2p^{6}3s^{2}$ .

And, atomic number of fluorine is 9 and its electronic configuration is $1s^{2}2s^{2}2p^{5}$ .

Therefore, magnesium needs to attain stability by losing two valence electrons and fluorine needs to attain stability by gaining one electron.

Hence, two fluorine atoms will chemically combine with one atom of magnesium to acquire stability.

Therefore, magnesium will donate its valence electron to each fluorine atom. This will form an ionic compound magnesium fluoride ( $MgF_{2}$ ).

Thus, we can conclude that magnesium and fluorine atoms most likely form an ionic bond.

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*multiple choice*

OleMash [197]

I think the answer is A but I could be wrong

4 0

3 years ago

Given the balanced equation representing a reaction:

notsponge [240]

Answer:

it is a base because they accept H+ ions

Explanation:

4 0

3 years ago

Determine the percent water in MgSO4*7H20?

Semmy [17]

Answer:

$\% H_2O=51.2\%$

Explanation:

Hello!

In this case, since the percent water is computed by dividing the amount of water by the total mass of the hydrate; we infer we first need the molar mass of water and that of the hydrate as shown below:

$MM_{MgSO_4* 7H_2O}=120.36 g/mol+7*18.02g/mol\\\\MM_{MgSO_4* 7H_2O}=246.5g/mol$

Thus, the percent water is:

$\% H_2O=\frac{7*MM_{H_2O}}{MM_{MgSO_4* 7H_2O}} *100\%\\\\$

So we plug in to obtain:

$\% H_2O=\frac{7*18.02}{246.5} *100\%\\\\\% H_2O=51.2\%$

Best regards!

5 0

2 years ago

Binary ionic compounds are named

aleksklad [387]

Binary compounds are easy to name. The cation is always named first and gets its name from the name of the element. For example, K+ is called a potassium ion. An anion also takes its name from its element, but it adds the suffix -ide to it.

8 0

3 years ago

In ionic bonding, during the transfer of electrons between two neutrally charged atoms, one electron moves from one atom to anot

forsale [732]

The given question is incomplete . The complete question is :

In ionic bonding, during the transfer of electrons between two neutrally charged atoms, one electron moves from one atom to another. What are the new relative charges between the two atoms?

a. The giving atom and receiving atom are both negatively charged

b. The giving atom is now positively charged and the receiving atom is now negatively charged.

c. The giving and receiving atom are both positively charged

d. The giving atom is now negatively charged and the receiving atom is now positively charged.

Answer: The giving atom is now positively charged and the receiving atom is now negatively charged.

Explanation:

Ionic compounds are formed by transference of electrons between metals and non metals. The bond formed between a metal and a non-metal is always ionic in nature.

For formation of a neutral ionic compound, the charges on cation and anion must be balanced. The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non metals.

Thus when one electron moves from one atom to another, the metal acquires a positive charge and the non metal acquires negative charge.

For example: $NaCl$ is formed by transfer of one electron from sodium to chlorine , thus forming $Na^+$ and $Cl^-$

3 0

3 years ago