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nlexa [21]
2 years ago
11

What is the multiplicative in verse of -1/14?

Mathematics
2 answers:
MatroZZZ [7]2 years ago
5 0

Answer:  -14

Step-by-step explanation:

The multiplicative inverse is the reciprocal of the number.

1/(-1/14) = -14

IrinaK [193]2 years ago
4 0

Answer:

<u>-14</u>

Step-by-step explanation:

one of the multiplicative inverses is the also the reciprocal of the number -14

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A King in ancient times agreed to reward the inventor of chess with one grain of wheat on the first of the 64 squares of a chess
statuscvo [17]
Let's start by visualising this concept.

Number of grains on square:
1   2   4   8   16 ...

We can see that it starts to form a geometric sequence, with the common ratio being 2.

For the first question, we simply want the fifteenth term, so we just use the nth term geometric form:
T_n = ar^{n - 1}
T_{15} = 2^{14} = 16384

Thus, there are 16, 384 grains on the fifteenth square.

The second question begs the same process, only this time, it's a summation. Using our sum to n terms of geometric sequence, we get:
S_n = \frac{a(r^{n} - 1)}{r - 1}
S_{15} = \frac{2^{15} - 1}{2 - 1}
S_{15} = 2^{15} - 1 = 32767

Thus, there are 32, 767 total grains on the first 15 squares, and you should be able to work the rest from here.
6 0
3 years ago
Read 2 more answers
Given that cos (x) = 1/3, find sin (90 - x)
ddd [48]

Answer:

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Step-by-step explanation:

Given: \cos (x)=\frac{1}{3}

We have to find the value of \sin(90^{\circ} - x)

Since Given \cos (x)=\frac{1}{3}

Using trigonometric identity,

\sin(90^{\circ} - \theta)=\cos\theta

Thus, for  \sin(90^{\circ} - x) comparing , we have,

\theta=x

We get,

\sin(90^{\circ} - x)=\cos x=\frac{1}{3}

Thus, \sin(90^{\circ} - x)=\frac{1}{3}

3 0
3 years ago
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Goshia [24]

Do we have to solve for M if so, the answer is

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8 0
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bearhunter [10]
The correct answer is -5
4 0
3 years ago
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What is the measure of angle 6, if lines x and y are parallel, and angle 7 measures 121°? 121° 69° 59° 49°
Marianna [84]

Answer:

59°

Step-by-step explanation:

From the diagram, shown in the attachment line x and y are parallel lines.

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\angle 7+\angle 6=180

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This implies that:

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Solve for angle 6 to get;

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7 0
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