2 years ago

Decompose x^2+4x-3/x-2

Mathematics

1 answer:

mariarad [96]2 years ago

5 0

Answer:

$\dfrac{x^3-2x^2+4x-3}{x-2}$

Step-by-step explanation:

The given equation is :

$x^2+\dfrac{4x-3}{x-2}$

We need to decompose this equation.

We have,

$x^2+\dfrac{4x-3}{x-2}\\\\=\dfrac{x^2(x-2)+4x-3}{x-2}\\\\=\dfrac{x^3-2x^2+4x-3}{x-2}$

So, $\dfrac{x^3-2x^2+4x-3}{x-2}$ is the decomposed form of the given expression.

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Decompose x^2+4x-3/x-2​

Decompose x^2+4x-3/x-2