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frez [133]
2 years ago
13

Decompose x^2+4x-3/x-2​

Mathematics
1 answer:
mariarad [96]2 years ago
5 0

Answer:

\dfrac{x^3-2x^2+4x-3}{x-2}

Step-by-step explanation:

The given equation is :

x^2+\dfrac{4x-3}{x-2}

We need to decompose this equation.

We have,

x^2+\dfrac{4x-3}{x-2}\\\\=\dfrac{x^2(x-2)+4x-3}{x-2}\\\\=\dfrac{x^3-2x^2+4x-3}{x-2}

So, \dfrac{x^3-2x^2+4x-3}{x-2} is the decomposed form of the given expression.

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When asked to find a number one-tenth as large as another number, what operation would you use? What about when asked to find a
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Apply division by 10 when one tenth of a number is required and apply multiplication by 10 when 10 times of a number is required.

<u>Solution:</u>

Need to determine what operation is required to get one-tenth of a number and 10 times of a number

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3 years ago
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