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frez [133]
3 years ago
13

Decompose x^2+4x-3/x-2​

Mathematics
1 answer:
mariarad [96]3 years ago
5 0

Answer:

\dfrac{x^3-2x^2+4x-3}{x-2}

Step-by-step explanation:

The given equation is :

x^2+\dfrac{4x-3}{x-2}

We need to decompose this equation.

We have,

x^2+\dfrac{4x-3}{x-2}\\\\=\dfrac{x^2(x-2)+4x-3}{x-2}\\\\=\dfrac{x^3-2x^2+4x-3}{x-2}

So, \dfrac{x^3-2x^2+4x-3}{x-2} is the decomposed form of the given expression.

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Polynomials are equations that uses variables and several terms

The polynomial in standard form is f(x) = x^2 - x -20

<h3>How to determine the polynomial</h3>

The polynomial has 2 zeros.

So, the form of the polynomial is:

f(x) = a(x - x1)(x - x2)

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So, the equation becomes

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So, we have;

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brainly.com/question/2833285

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