Question

Decompose x^2+4x-3/x-2​

Answer 1

Answer:

$\dfrac{x^3-2x^2+4x-3}{x-2}$

Step-by-step explanation:

The given equation is :

$x^2+\dfrac{4x-3}{x-2}$

We need to decompose this equation.

We have,

$x^2+\dfrac{4x-3}{x-2}\\\\=\dfrac{x^2(x-2)+4x-3}{x-2}\\\\=\dfrac{x^3-2x^2+4x-3}{x-2}$

So, $\dfrac{x^3-2x^2+4x-3}{x-2}$ is the decomposed form of the given expression.