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frez [133]
3 years ago
13

Decompose x^2+4x-3/x-2​

Mathematics
1 answer:
mariarad [96]3 years ago
5 0

Answer:

\dfrac{x^3-2x^2+4x-3}{x-2}

Step-by-step explanation:

The given equation is :

x^2+\dfrac{4x-3}{x-2}

We need to decompose this equation.

We have,

x^2+\dfrac{4x-3}{x-2}\\\\=\dfrac{x^2(x-2)+4x-3}{x-2}\\\\=\dfrac{x^3-2x^2+4x-3}{x-2}

So, \dfrac{x^3-2x^2+4x-3}{x-2} is the decomposed form of the given expression.

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Read 2 more answers
Why did I get this question wrong?
lord [1]

Step-by-step explanation:

∫₀³⁰ (r/V C₀ e^(-rt/V)) dt

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I got the same answer.  Try changing the lowercase v to an uppercase V.

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