Ask question

Ask question

All categories

3 years ago

9

The formula E= MHz, where E = gravitational potential energy , mass, g = gravity, and h= Height, is used to calculate gravitatio

nal potential energy. Solve this formula for h.

1 answer:

nikdorinn [45]3 years ago

5 0

The anwser to the question is MH+E=24

You might be interested in

The pool at the apartment building is 30 feet long, 20 feet wide, and 5 feet deep. It has been filled 4 feet deep. How many more

egoroff_w [7]

I think the answer is A 600 cubic feet

6 0

3 years ago

Find the domain and range of f(x) = 2 square root of x-2

Neporo4naja [7]

$f(x)=2\sqrt{x-2}\\\\The\ domain:\\x-2\geq0\to x\geq2\\\boxed{x\in[2;\ \infty)}\\\\The\ range:\\\boxed{y\in[0;\ \infty)}$

$If\ f(x)=2\sqrt{x}-2,\ then\\\\The\ domain:\boxed{x\in[0;\ \infty)}\\\\The\ range:\boxed{y\in[-2;\ \infty)}$

5 0

3 years ago

A square piece of cardboard has sides that are 7/12 meter long. What is the carb words perimeter

gavmur [86]

Since it’s a square all sides are even. Meaning you multiply 7/12 by 4. Giving you 7/3 or 2 ⅓. Hope this helps!

6 0

3 years ago

Fifty-three percent of employees make judgements about their co-workers based on the cleanliness of their desk. You randomly sel

GarryVolchara [31]

Answer:

The unusual $X$ values for this model are: $X = 0, 1, 2, 7, 8$

Step-by-step explanation:

A binomial random variable $X$ represents the number of successes obtained in a repetition of $n$ Bernoulli-type trials with probability of success $p$ . In this particular case, $n = 8$ , and $p = 0.53$ , therefore, the model is ${8 \choose x} (0.53) ^ {x} (0.47)^{(8-x)}$ . So, you have:

$P (X = 0) = {8 \choose 0} (0.53) ^ {0} (0.47) ^ {8} = 0.0024$

$P (X = 1) = {8 \choose 1} (0.53) ^ {1} (0.47) ^ {7} = 0.0215$

$P (X = 2) = {8 \choose 2} (0.53)^2 (0.47)^6 = 0.0848$

$P (X = 3) = {8 \choose 3} (0.53) ^ {3} (0.47)^5 = 0.1912$

$P (X = 4) = {8 \choose 4} (0.53) ^ {4} (0.47)^4} = 0.2695$

$P (X = 5) = {8 \choose 5} (0.53) ^ {5} (0.47)^3 = 0.2431$

$P (X = 6) = {8 \choose 6} (0.53) ^ {6} (0.47)^2 = 0.1371$

$P (X = 7) = {8 \choose 7} (0.53) ^ {7} (0.47)^ {1} = 0.0442$

$P (X = 8) = {8 \choose 8} (0.53)^{8} (0.47)^{0} = 0.0062$

The unusual $X$ values for this model are: $X = 0, 1, 7, 8$

6 0

4 years ago

Read 2 more answers

During the 2005 football season, Team Tackle beat Team Sack by 6 points. If their combined scores totaled 60, find the individ

Travka [436]

2x+6=60

2x=60-6

2x=54

x=54/2

x=27

27+27+6=60

8 0

3 years ago