a steel suitable for making nails is melleable and ductile.what can you infer about the probable carbon content of the steel.

Why do plant cells need both chloroplasts and mitochondria?

nevsk [136]

They both perform photosynthesis and also cell respiration

4 0

3 years ago

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What is defined as the basic unit in the metric system that describes a quality

Natasha2012 [34]

$\huge\blue{\mid{\fbox{\tt{your~\:QUESTION}}\mid}}$

What is defined as the basic unit in the metric system that describes a quality?

Answer:

the metric system is a system of measurement that uses the meter, liter, and gram as base units of length (distance), capacity (volume), and weight (mass) respectively.

:D Hope this helps!

6 0

3 years ago

How many grams of sodium oxide can be produced when 55.3 g Na react with 64.3 g O2?

zimovet [89]

Answer : The amount of sodium oxide produced is, 74.40 grams

Solution : Given,

Mass of sodium = 55.3 g

Mass of $O_2$ = 64.3 g

Molar mass of sodium = 23 g/mole

Molar mass of $O_2$ = 32 g/mole

Molar mass of $Na_2O$ = 61.9 g/mole

First we have to calculate the moles of sodium and oxygen.

Moles of Na = $\frac{\text{ given mass of Na}}{\text{ molar mass of Na}}= \frac{55.3g}{23g/mole}=2.404moles$

Moles of $O_2$ = $\frac{\text{ given mass of }O_2}{\text{ molar mass of }O_2}= \frac{64.3g}{32g/mole}=2.009moles$

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction will be,

$4Na+O_2\rightarrow 2Na_2O$

From the balanced reaction we conclude that

4 moles of sodium react with 1 mole of oxygen

2.404 moles of sodium react with $\frac{2.404}{4}=0.601$ moles of oxygen

Excess moles of oxygen = 2.009 - 0.601 = 1.408 moles

That means sodium is a limiting reagent and oxygen is an excess reagent.

Now we have to calculate the moles of sodium oxide.

From the reaction we conclude that,

4 moles of sodium react to give 2 moles of sodium oxide

2.404 moles of sodium react to give $\frac{2}{4}\times 2.404=1.202$ moles of sodium oxide

Now we have to calculate the mass of sodium oxide.

$\text{Mass of }Na_2O=\text{Moles of }Na_2O\times \text{Molar mass of }Na_2O$

$\text{Mass of }Na_2O=(1.202moles)\times (61.9g/mole)=74.40g$

Therefore, the amount of sodium oxide produced is, 74.40 grams

5 0

3 years ago

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What does the second quantum number (1) describe?

natima [27]

Answer:

Which sublevel the electron is in

Explanation:

a-p-e-x

3 0

3 years ago

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If 1 gram of calcium chloride is dissolved in 100 mL of pure water, what temperature change will be observed

svp [43]

Explanation:

It is known that the molecular weight of $CaCl_{2}$ is 111 g/mol. This means that 1 mole of $CaCl_{2}$ contains 111 g $CaCl_{2}$ .

1 g $CaCl_{2}$ = $\frac{1}{111} mol CaCl_{2}$

As we know that the density of water is 1 g/cc (as 1 ml = 1 cc).

So, 100 ml water = 100 g water. Therefore, in 100 g of water $CaCl_{2}$ present will be calculated as follows.

$\frac{1}{111}$ mol

So, in 1000 g water the amount of $CaCl_{2}$ present will be calculated as follows.

$\frac{1 \times 1000}{111 \times 100}$

= 0.09 mol

Hence, the molality of $CaCl_{2}$ is 0.09 mol.

According to Raoult's law,

$\Delta T_{b} = K_{b} \times m$

where, $K_{b}$ = boiling point constant

For pure 1 kg water, $K_{b}$ = 0.52 K.kg/mol

m = molality of solution

Therefore, putting the given values into the above formula as follows.

$\Delta T_{b} = K_{b} \times m$

= $0.52 K m^{-1} \times 0.09 m$

= 0.0468 K

Therefore, the boiling point will raise by 0.0468 K.

4 0

3 years ago

a steel suitable for making nails is melleable and ductile.what can you infer about the probable carbon content of the steel.​

a steel suitable for making nails is melleable and ductile.what can you infer about the probable carbon content of the steel.