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2 years ago

Essay on Outdoor skills

Physics

1 answer:

den301095 [7]2 years ago

7 0

Answer and Explanation:

I can't write the essay for you, but I can give you useful tips on what information should be in your essay.

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Outdoor skills basically have a similar concept to street smarts. With street smarts, you are knowledgeable in what to do on the streets, how to act, what signs and signals to look out for, and other things like that. With outside smarts, it's the same way. Except, I would say that it is a little less social.

Outside smarts could be something like camping, and surviving in general in the wild, such as:

- Creating a tent or shelter for yourself to sleep in.

- Finding food and knowing whether it is acceptable and safe to eat.

- Making sure that you are in a safe area that is okay for you to camp out in.

- Making sure that you have some sort of protection, whether that would be with a weapon, a tool, or something else.

- Making sure that you have safe water to drink that you brought with you.

- A back-up plan in case there is a reason that you need to leave.

- A first aid kit in case of injury.

- How to create a fire and use it safely.

- A way to get back home, with a plan and possibly even a compass.

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I hope that this helps.

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Addition of a metal slab of thickness "a" between the plates of a parallel plate capacitor of plate separation "d" is equivalent

Crazy boy [7]

Answer:

$K = \frac{d}{d+a}$

Explanation:

The capacitance of a capacitor in terms of the dielectric constant, area of the plate and the distance separating the plate is given by:

$C = \frac{\epsilon A}{d}$

Where A = Area of the plate

d = distance between the plates

$\epsilon =$ dielectric constant

Case 1:

When a meta slab of thickness, a, is added between the plates of the parallel plate capacitor , the effective separation between the plates becomes d+a

Therefore the capacitance of the capacitor becomes:

$C = \frac{\epsilon A}{d + a}$ .......................(1)

Case 2:

Introducing a dielectric with dielectric constant K between the plates, the capacitance of the capacitor becomes:

$C = \frac{K\epsilon A}{d}$ .........................(2)

Equating (1) and (2)

$\frac{K\epsilon A}{d} = \frac{\epsilon A}{d+a}\\\frac{K}{d} = \frac{1}{d+a} \\K = \frac{d}{d+a}$

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3 years ago

Explain why air masses do not mix

kati45 [8]

Different densities have to have a reason - different pressure and/or humidity etc. If there is a different pressure, there is a mechanical force that preserves the pressure difference: think about the cyclones that have a lower pressure in the center. The cyclones rotate in the right direction and the cyclone may be preserved by the Coriolis force.

If the two air masses differ by humidity, the mixing will almost always lead to precipitation - which includes a phase transition for water etc. It's because the vapor from the more humid air mass gets condensed under the conditions of the other. You get some rain. In general, intense precipitation, thunderstorms, and other visible isolated weather events are linked to weather fronts.

At any rate, a mixing of two air masses is a nontrivial, violent process in general. That's why the boundary is called a "front". In the military jargon, a front is the contested frontier of a conflict. So your idea that the air masses could mix quickly and peacefully - whatever you exactly mean quantitatively - either neglects the inertia of the air, a relatively low diffusion coefficient, a low thermal conductivity, and/or high latent heat of water vapor. A front is something that didn't disappear within minutes so pretty much tautologically, there must be forces that make such a quick disappearance impossible.

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3 years ago

5. Which organisms are used to manufacture human insulin?

earnstyle [38]

The answer is going to be C, Bacteria. Therefore the organisms that are used to manufacture human insulin would be bacteria.

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3 years ago

Who is the founder of operant conditioning?

Gemiola [76]

Operant conditioning, sometimes called <em>instrumental learning</em>, was first extensively studied by Edward L. Thorndike, who observed the behavior of cats trying to escape from home-made puzzle boxes.

Hope this helps!

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3 years ago

Problem 3: Thermal expansionThe steel rod has the length 2 m and cross-section area 200 cm2at the room temperature 20◦C. Weapply

zalisa [80]

Answer:

a) 2.00024 m

b) 0.036%

c) 436.67°C

Explanation:

Given

Initial length = L₀ = 2 m

Initial cross sectional Area = A₀ = 200 cm² = 0.02 m²

We can obtain initial volume = V₀ = A₀L₀ = 0.02 × 2 = 0.04 m³

Initial Temperature = T₀ = 20°C

Coefficient of linear expansivity = α = (2 × 10⁻⁶) (°C)⁻¹

a) New length of the rod after heating to 80°C

Linear expansion is given as

ΔL = L₀ × α ×ΔT

ΔL = 2 × 2 × 10⁻⁶ × (80 - 20) = 0.00024 m = 0.24 mm

New length = old length + expansion = 2 + 0.00024 = 2.00024 m

b) The percentage of the volume change of the rod.

Volume expansion is given by

ΔV = V₀ × (3α) × ΔT

Volume expansivity ≈ 3 × (linear expansivity)

ΔV = 0.04 × (3×2×10⁻⁶) × (80 - 20) = 0.0000144 m³

Percentage change in volume = 100% × (ΔV/V₀) = 100% × (0.0000144/0.04) = 0.036%

c) The maximal temperature we can allow if the volume should not increase by more than half percent.

For a half percent increase in volume, the corresponding change in volume needs to be first calculated.

Percentage change in volume = 100% × (ΔV/V₀)

0.5 = 100% × (ΔV/0.04)

(ΔV/0.04) = 0.005

ΔV = 0.0002 m³

Then we now investigate the corresponding temperature that causes this.

ΔV = V₀ × (3α) × ΔT

0.0002 = 0.04 × (3×2×10⁻⁶) × ΔT

ΔT = (0.0002)/(0.04 × 3 × 2 × 10⁻⁶) = 416.67°C

Maximal temperature = T₀ + ΔT = 20 + 416.67 = 436.67°C

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3 years ago