An underwater air bubble has an excess inside pressure of 13 pa. what is the excess pressure inside an air bubble with twice the
radius?
1 answer:
Pressure = 2 * pi * sigma * radius where sigma is the pressure constant of the medium or the material.
Thus, Pressure/Radius = constant
Based on this:
(pressure*radius) in case 1 = (pressure*radius) in case 2
(13 * R) = (P * 2R)
P = 13/2 = 6.5 pa
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