Answer:
Quarks
Explanation:
Quarks, the smallest particles in the universe, are far smaller and operate at much higher energy levels than the protons and neutrons in which they are found.
Answer:
Explanation:
Sun's dynamo means the process that produce Sun's magnetic field.
The mechanism inside a Sun acts like a generator that produces electric current and magnetic field.
Magnetic field with in the Sun are extended out and around. Magnetic field of lines get twisted due to rotation of Sun.
The material that flows inside the Sun plays an important role in Sun's dynamo. At surface the flow rate is about 20 m/s but as it moves towards equator, it becomes way too slow taking about 11 years of time.
Due to the this magnetic field, several sun spots are formed on the surface.
The number of sunspots keep on changing from minimum to maximum number resulting into change in the magnetic pole. In each cycle polarity get reversed hence the overall magnetic cycle has an interval of 22 years.
Answer:
Torque is 93 Nm anticlockwise.
Explanation:
We have value of torque is cross product of position vector and force vector.
A force of 38 N, directed 30° above the x axis in the x-y plane.
Force, F = 38 cos 30 i + 38 sin 30 j = 32.91 i + 19 j
A particle is located on the x axis 4.9 m and we have to find torque about the origin on the particle.
Position vector, r = 4.9 i
Torque, T = r x F = 4.9 i x (32.91 i + 19 j) = 4.9 x 19 k = 93.1 k Nm
So Torque is 93 Nm anticlockwise.
Answer: The right answer is b)
Explanation:
By definition, acceleration is the change in velocity (in module or direction) over a given time interval, as follows:
a = (v-v₀) / (t-t₀)
If we take t₀ = 0 (this is completely arbitrary), we can rewrite the equation above, as follows:
v = v₀ + at
We can recognize this function as a linear one, where a represents the slope of the line.
If a is constant, this means that the relationship between the change in velocity and the change in time remains constant, in other words, in equal times, its velocity changes in an equal amount.
Let's suppose that a = 10 m/s/s. (Usually written as 10 m/s²).
This is telling us that each second, the velocity increases 10 m/s.
Answer:
minimum length of runway is needed for take off 243.16 m
Explanation:
Given the data in the question;
mass of glider = 700 kg
Resisting force = 3700 N one one glider
Total resisting force on both glider = 2 × 3700 N = 7400 N
maximum allowed tension = 12000 N
from the image below, as we consider both gliders as a system
Equation force in x-direction
2ma = T -f
a = T-f / 2m
we substitute
a = (12000 - 7400 ) / (2 × 700 )
a = 4600/1400
a = 3.29 m/s²
Now, let Vf be the final speed and Ui = 0 ( as starts from rest )
Vf² = Ui² + 2as
solve for s
Vf² = 0 + 2as
2as = Vf²
s = Vf² / 2a
given that take of speed for the gliders and the plane is 40 m/s
we substitute
s = (40)² / 2×3.29
s = 1600 / 6.58
s = 243.16 m
Therefore, minimum length of runway is needed for take off 243.16 m
