All categories

3 years ago

What is the cost of conserved energy for compact fluorescent lighting?

Physics

1 answer:

jonny [76]3 years ago

7 0

Typically use 25% -80% less energy than traditional
-incandescents, saves you money
-can last 3-25 times longer

You might be interested in

Absolute zero (K=0 or -273.15°C) is what temperature on the Farenheit scale? a) 459.4°F b) -301.43 °F c) 233.05°F d) -40.15°F e

ANEK [815]

Answer:

e) None of these is true

Explanation:

Given that

Temperature = 0 K

We know that relationship between kelvin and Farenheit scale

$\dfrac{K-273}{100}=\dfrac{F-32}{180}$

Now by putting the values

$\dfrac{K-273}{100}=\dfrac{F-32}{180}$

$\dfrac{0-273}{100}=\dfrac{F-32}{180}$

So F= - 459.67°F

So we can say that 0 K is equal to - 459.67°F.

So the our option e is correct.

3 0

4 years ago

A motorcycle being driven on a dirt path hits a

Colt1911 [192]

Impulse = mass * change in velocity (change in momentum) = Force * change in time

So, F=(m*change in v)/(change in t)
F=(60*20)/0.5=2400N

Therefore the magnitude of the average force exerted on the cyclist by the haystack is 2.4*10^3N

4 0

4 years ago

If matter cannot be created nor destroyed the how was matter created

Assoli18 [71]

It can’t be created nor destroyed although it can be changed from one form to the other

I hope this helps

Have a happy holidays:)

7 0

3 years ago

A 66-kg fellow stands on a digital scale in an elevator that accelerates upwards from rest to 4.5 m/s in 2.00 s. show answer Inc

Nina [5.8K]

Answer:

Explanation:

mass of the fellow ( m ) = 66kg

acceleration of fellow a

v = u + at

4.5 = 0 + a x 2

a = 4.5 /2

= 2.25 m / s²

Net force acting on fellow in upward direction by the surface of elevator

R - mg where R is reaction force of the surface of the elevator

Applying Newton's law of motion

R - mg = ma

R = m (g +a )

= 66 x ( 9.8 + 2 )

= 778.8 N

This will be the scale reading .

7 0

3 years ago

A small charged sphere is attached to a thread and placed in an electric field. The other end of the thread is anchored so that

VMariaS [17]

Answer:

$E = 9.66\times 10^{-6} N/C$

direction is Horizontal

Explanation:

As we know that the string is horizontal here

so the tension force in the string is due to electrostatic force on it

now we will have

$F = qE$

so here the force is tension force on it

$F = 6.57 \times 10^{-2} N$

$Q = 6.80 \times 10^3 C$

now we have

$6.57 \times 10^{-2} = (6.80 \times 10^3)E$

$E = 9.66\times 10^{-6} N/C$

direction is Horizontal

4 0

4 years ago