To solve this problem we will start by differentiating the values in each of the states of matter. Subsequently through the thermodynamic tables we will look for the values related to the entropy, enthalpy and respective specific volumes. Through the relationship of Power defined as the product between mass and enthalpy and mass, specific volume and pressure, we will find the energetic values in the two states investigated. We will start defining the states
State 1
From steam table
Now
<em>As 1-2 is isentropic</em>
State 2
From steam table
PART A) The power produced by turbine is the product between the mass and the enthalpy difference, then
b) Pump Work
State 3
The Work done by the pump is
Galaxy M33 is classified as a Triangulum normal spiral.
The galaxy M33 is the third largest galaxy in the Local Group after M31 and the Milky Way. The galaxy M33 has a moderate-sized central bulge and two spiral arms that emerge directly out of the bulge and wrap around in rather poorly defined arcs with many cross-connections between the arms.
This spiral galaxy is located in the triangle shaped constellation earning a pet name as triangular galaxy. This galaxy star formation rate is ten times higher than average found in Andromeda galaxy. It has relatively bright apparent. This galaxy was given by Charles Messier and he classified it as Triangulum normal spiral.
Learn more about galaxy here:
brainly.com/question/13074009
#SPJ4
Answer:
The formula for Impedance for circuit with R, C, and L are:
The impedance Z of the series RLC circuit depend upon angular frequency ω. Impedance is measured in ohms and resistance (R), inductance reactance and capacitive reactance. Series RLC circuit consist of the resistance, a capacitance and an inductance connected in the circuits. Electrical impedance is the measurement of the opposition that a circuit present in a current.
Answer:
a scientific law must be universally correct there could be no contradictions regarding the law anywhere
Answer:
v₃ = 9.62[m/s]
Explanation:
To solve this type of problem we must use the principle of conservation of linear momentum, which tells us that the momentum is equal to the product of mass by velocity.
We must analyze the moment when the astronaut launches the toolkit, the before and after. In order to return to the ship, the astronaut must launch the toolkit in the opposite direction to the movement.
Let's take the leftward movement as negative, which is when the astronaut moves away from the ship, and rightward as positive, which is when he approaches the ship.
In this way, we can construct the following equation.
where:
m₁ = mass of the astronaut = 157 [kg]
m₂ = mass of the toolkit = 5 [kg]
v₁ = velocity combined of the astronaut and the toolkit before throwing the toolkit = 0.2 [m/s]
v₂ = velocity for returning back to the ship after throwing the toolkit [m/s]
v₃ = velocity at which the toolkit should be thrown [m/s]
Now replacing:
![-(157+5)*0.2=(157*0.1)-(5*v_{3})\\(5*v_{3})= 15.7+32.4\\v_{3}=9.62[m/s]](https://tex.z-dn.net/?f=-%28157%2B5%29%2A0.2%3D%28157%2A0.1%29-%285%2Av_%7B3%7D%29%5C%5C%285%2Av_%7B3%7D%29%3D%2015.7%2B32.4%5C%5Cv_%7B3%7D%3D9.62%5Bm%2Fs%5D)
