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olga55 [171]
3 years ago
12

1x+11y=55 substitution

Mathematics
1 answer:
STatiana [176]3 years ago
4 0

Answer:

y = -1/11 + 5

Step-by-step explanation:

1x + 11y = 55

-1x          -1x

11y = -1x + 55

/11        /11

y = -1/11 + 5

Hope this helps!

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7. Calculate the selling price of a $350 camera with a 35% mark-up sale price.
lubasha [3.4K]

Answer:

10) 3/5=a/15

a=9

9) 6/100×300

18$

8) 100-57.5

=42.5percent

7) 35/100×350

.=$122.5

3 0
4 years ago
Three six-sided fair dice are rolled. The six sides of each die are numbered 1; 2; : : : ; 6. Let A be the event that the first
valkas [14]

Answer:

1.) [A, B, C]

2.) [A', B', C']

3.) [A', B, C] or [A, B', C] or [A, B, C'] or [ A', B', C] or [A', B, C'] or [A, B', C'] or [A', B', C']

4.) A', B', C] or [A', B, C'] or [A, B', C'] or [A', B, C] or [A, B', C] or [A, B, C'] or [A, B, C]

Step-by-step explanation:

If A is the event that the first die shows an even number, then A' is the event that first die DOES NOT show an even number.

If B is the event that the Second die shows and even number, then B' is the event that second die DOES NOT show an even number.

If C is the event that the third die shows an even number, then C' is the event that third die DOES NOT show an even number.

Hence, our possible events are A, A', B, B', C, C'.

For question 1, in the event that all three dice show and even number, the expression of the event = [A, B, C]

For question two, in the event that no die shows an even number, the expression of the event = [A', B', C']

For question 3,In the event that at least one die shows an odd number, the expression of the event = [A', B, C] or [A, B', C] or [A, B, C'] or [ A', B', C] or [A', B, C'] or [A, B', C'] or [A', B', C']

For question 4,in the event that at most two dice show odd numbers, the expression of the event = [A', B', C] or [A', B, C'] or [A, B', C'] or [A', B, C] or [A, B', C] or [A, B, C'] or [A, B, C]

6 0
3 years ago
What is the quotient [3y+2/3y] / [6y^2+4y/3y+2]
givi [52]
<span>[3y+2/3y] / [6y^2+4y/3y+2]
Steps
First, divide fractions
= (3y + 2)(3y + 2)/3y(6y^2 + 4y)
Then... factor 3y(6y^2 + 4y): 6y^2(3y + 2)
= (3y + 2)(3y + 2)/6y^2(3y + 2)
Then, cancel the common factor: 3y + 2
= 3y + 2/6y^2</span>
6 0
4 years ago
Read 2 more answers
The volume of triangular prims.
Nat2105 [25]

Check the picture below.

so we really have 2 equal triangles with 3 rectangles, so let's get the area of each and sum them up.

\stackrel{\textit{two equal triangles}}{2\left[ \cfrac{1}{2}(8)(6) \right]}~~+~~\stackrel{back}{(6\cdot 4)}~~ +~~\stackrel{bottom}{(8\cdot 4)}~~+~~\stackrel{top}{(10\cdot 4)}\implies 144

4 0
2 years ago
Can someone help me how would you eliminate the “y”
saw5 [17]

Answer:

Multiply by 3 -> 3(x - y = 6)

Step-by-step explanation:

Cuz since the 2nd is positive 3y

u need a negative 3y to get rid of it

3(x - y = 6)

2x + 3y = 7

3x - 3y = 18

2x + 3y = 7

5x/5 = 25/5

x = 5

5 - y = 6

-5          -5

-y/-1= 1/-1

y = -1

(5,-1)

8 0
3 years ago
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