(a) 
The change in potential energy of the electron is given by:
where
is the magnitude of the electron's charge
is the magnitude of the electric field
d = 520 m is the distance through which the electron has moved
Substituting into the equation, we find
(b) 78 kV
The potential difference the electron has moved through is given by
where
is the magnitude of the electric field
d = 520 m is the distance through which the electron has moved
Substituting into the equation, we find
U = I × R = 20A × 12 Ohm =240V
Answer:
The magnitude of the average induced emf is 90V
Explanation:
Given;
area of the square coil, A = 0.4 m²
number of turns, N = 15 turns
magnitude of the magnetic field, B = 0.75 T
time of change of magnetic field, t = 0.05 s
The magnitude of the average induced emf is given by;
E = -NAB/t
E = -(15 x 0.4 x 0.75) / 0.05
E = -90 V
|E| = 90 V
Therefore, the magnitude of the average induced emf is 90V
I think it is acceleration
Displacement (s) of an object equals, velocity (u) times time (t), plus ½ times acceleration (a) times time squared (t2). Use standard gravity, a = 9.80665 m/s2, for equations involving the Earth's gravitational force as the acceleration rate of an object.
