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Kisachek [45]
2 years ago
7

How does forces affect the acceleration of a body

Physics
2 answers:
yaroslaw [1]2 years ago
4 0
The acceleration of an object depends directly upon the net force acting upon the object, and inversely upon the mass of the object. As the force acting upon an object is increased, the acceleration of the object is increased. As the mass of an object is increased, the acceleration of the object is decreased.
liq [111]2 years ago
3 0

Answer:

gravity, and mass

Explanation:

Gravity will pull down on you and mass or how much you weigh will make you fall down faster slowly making you gain speed

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How do the forces on a skydiver affect the velocity of the skydiver as they fall?<br><br><br> Hellp
solmaris [256]

Answer:

Explanation:

As a skydiver falls, he accelerates downwards, gaining speed with each second. The increase in speed is accompanied by an increase in air resistance. This force of air resistance counters the force of gravity.

3 0
3 years ago
Read 2 more answers
The formula $F = \frac{9}{5} C + 32$ can be used to convert temperatures between degrees Fahrenheit ($F$) and degrees Celsius ($
slamgirl [31]

Answer:

-30° C

Explanation:

Data provided in the problem:

The formula for conversion as:

F  = (9/5)C + 32

Now,

for the values of F = -22 , C = ?

Substituting the value of F in the above formula, we get

-22 = (9/5)C + 32

or

-22 - 32 = (9/5)C

or

(9/5)C = - 54

or

C = - 54 × (5/9)

or

C = - 30 °

Hence, -22 Fahrenheit equals to -30°C

7 0
3 years ago
Sort the statements about heat transfer into the correct columns.
Hoochie [10]

Answer: Conduction- Touch transfer heat and Earth warms air

Convection- liquid/gas transfers heat and warm air rises

Radiation- Sun heats Earth and Waves transfer heat

Explanation:

5 0
4 years ago
Read 2 more answers
NEED HELP NOW ETHANHUNT 25 POINTS WILL MARK BRAINLIEST!! For the independent reading all you have to do is pick a grade six book
garik1379 [7]
Can you please stop pasting this question, just go to his profile and ask him.
7 0
3 years ago
Consult interactive solution 2.22 before beginning this problem. a car is traveling along a straight road at a velocity of +30.0
Inessa05 [86]

Let a_1 be the average acceleration over the first 2.46 seconds, and a_2 the average acceleration over the next 6.79 seconds.

At the start, the car has velocity 30.0 m/s, and at the end of the total 9.25 second interval it has velocity 15.2 m/s. Let v be the velocity of the car after the first 2.46 seconds.

By definition of average acceleration, we have

a_1=\dfrac{v-30.0\,\frac{\mathrm m}{\mathrm s}}{2.46\,\mathrm s}

a_2=\dfrac{15.2\,\frac{\mathrm m}{\mathrm s}-v}{6.79\,\mathrm s}

and we're also told that

\dfrac{a_1}{a_2}=1.66

(or possibly the other way around; I'll consider that case later). We can solve for a_1 in the ratio equation and substitute it into the first average acceleration equation, and in turn we end up with an equation independent of the accelerations:

1.66a_2=\dfrac{v-30.0\,\frac{\mathrm m}{\mathrm s}}{2.46\,\mathrm s}

\implies1.66\left(\dfrac{15.2\,\frac{\mathrm m}{\mathrm s}-v}{6.79\,\mathrm s}\right)=\dfrac{v-30.0\,\frac{\mathrm m}{\mathrm s}}{2.46\,\mathrm s}

Now we can solve for v. We find that

v=20.8\,\dfrac{\mathrm m}{\mathrm s}

In the case that the ratio of accelerations is actually

\dfrac{a_2}{a_1}=1.66

we would instead have

\dfrac{15.2\,\frac{\mathrm m}{\mathrm s}-v}{6.79\,\mathrm s}=1.66\left(\dfrac{v-30.0\,\frac{\mathrm m}{\mathrm s}}{2.46\,\mathrm s}\right)

in which case we would get a velocity of

v=24.4\,\dfrac{\mathrm m}{\mathrm s}

6 0
3 years ago
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