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cestrela7 [59]
4 years ago
6

If a golf ball and a ping-pong ball both move with the same kinetic energy, can you say which has the greater speed? Explain in

terms of KE. Similarly, in a gaseous mixture of massive molecules and light molecules with the same average KE, can you say which has the greater speed?
Physics
1 answer:
Elodia [21]4 years ago
6 0

Answer:

The ping pong ball, the light molecules have greater speed

Explanation:

The kinetic energy of an object is defined as

K=\frac{1}{2}mv^2

where

m is the mass of the object

v is its speed

It follows that the speed can be written as

v=\sqrt{\frac{2K}{m}}

In this problem, both the golf ball and the ping pong ball have kinetic energy K. However, the mass of a gold ball is larger (approx. 45 g) than that of a ping pong ball (approx. 4 g): therefore, since v is inversely proportional to the square root of the mass, it follows that the ping pong ball must have a greater speed in order to achieve the same kinetic energy of the golf ball.

The same argument can be applied to the gaseous mixture: if there are more massive molecules and light molecules, and if they all have the same kinetic energy, then this means that the light molecules must have a greater speed, as a result again of the equation

v=\sqrt{\frac{2K}{m}}

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Answer:

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3 years ago
A double slits separated by 0.0580 mm is located at a distance of 1.50 m from a screen. (a) If yellow light of wavelength 588 nm
serg [7]

Answer:

The separation between third order and first order is 0.0304 m

Explanation:

Given:

Separation between two slit d = 0.0580 \times 10^{-3} m

Distance between slit and screen D = 1.50 m

Wavelength of light \lambda = 588 \times 10^{-9} m

From the formula of interference of light,

    d \sin \theta = n\lambda

Here \sin \theta = \frac{x}{D}

 \frac{dx}{D}  = n \lambda

   x = \frac{n\lambda D}{d}

Where x = separation between fringes

Here we have to find between third order and first order,

   x = \frac{(n_{3} - n_{1})\lambda D }{d}

Where n_{3} = 3   n_{1} = 1

   x = \frac{2 \times 588 \times 10^{-9} \times 1.50}{0.0580 \times 10^{-3} }

   x = 0.0304 m

Therefore, the separation between third order and first order is 0.0304 m

4 0
3 years ago
A wave carries___<br> from one place to another.<br> Mechanical waves carry energy through ___
saul85 [17]

Answer:

Energy

A medium

Explanation:

A wave is a disturbance that travels through a medium, transferring energy from one point to another in the medium.

Mechanical waves are waves that require a medium for their propagation.

4 0
3 years ago
Read 2 more answers
How do you find distance on a velocity time graph?
vekshin1

The region under the speed time chart gives the relocation.  

In simple to-recall, straightforward terms, remove levels with the result of speed and time. So when you discover the region under a speed time diagram, you are really increasing speed and time. This gives the separation.

8 0
3 years ago
An object travels along a straight line across a horizontal surface, and its motion is described by the velocity versus time gra
Mkey [24]

Answer:

C.)Finding the area bound by the horizontal axis and the curve from 0 s to 5 s

D.)Using Average Speed = total distance/total and multiplying the average speed of 5m/s by a total time of 5 s

Explanation:

The graph seems to be missing, however we can still answer the question.

In fact, we have to keep in mind the following facts:

- In a velocity-time graph, the area under the curve represents the displacement of the object, while the slope of the curve corresponds to its acceleration.

From this, we can already say that the following option:

C.)Finding the area bound by the horizontal axis and the curve from 0 s to 5 s

is correct, while the statement

A.)Finding the slope of the line between 0 s to 5 s

is wrong.

Moreover, the average speed of an object in motion is given by

v=\frac{d}{t}

where d is the total distance covered while t is the total time taken. Once we have calculated the average speed, the total displacement over a certain time period can be simply calculated by multiplying the average speed by the time interval: so, the option

D.)Using Average Speed = total distance/total and multiplying the average speed of 5m/s by a total time of 5 s

is also correct.

The last option remained:

B.)Dividing the change in velocity between 0 s to 5 s by the change in time

is wrong, because in this way we are calculating the acceleration, not the displacement.

6 0
3 years ago
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