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cestrela7 [59]
4 years ago
6

If a golf ball and a ping-pong ball both move with the same kinetic energy, can you say which has the greater speed? Explain in

terms of KE. Similarly, in a gaseous mixture of massive molecules and light molecules with the same average KE, can you say which has the greater speed?
Physics
1 answer:
Elodia [21]4 years ago
6 0

Answer:

The ping pong ball, the light molecules have greater speed

Explanation:

The kinetic energy of an object is defined as

K=\frac{1}{2}mv^2

where

m is the mass of the object

v is its speed

It follows that the speed can be written as

v=\sqrt{\frac{2K}{m}}

In this problem, both the golf ball and the ping pong ball have kinetic energy K. However, the mass of a gold ball is larger (approx. 45 g) than that of a ping pong ball (approx. 4 g): therefore, since v is inversely proportional to the square root of the mass, it follows that the ping pong ball must have a greater speed in order to achieve the same kinetic energy of the golf ball.

The same argument can be applied to the gaseous mixture: if there are more massive molecules and light molecules, and if they all have the same kinetic energy, then this means that the light molecules must have a greater speed, as a result again of the equation

v=\sqrt{\frac{2K}{m}}

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An electron moving with a velocity v= 5.0 × 107 m/s i enters a region of space where perpendicular electric and a magnetic field
liq [111]

Answer:

The magnetic field that will allow the electron to go through the region without being deflected is 2\times 10^{-4}\ T.

Explanation:

Given that,

Velocity of the electron, v=5\times 10^7\ m/s

Electric field, E=10^4\ V/m\ j

We need to find the magnetic field that will allow the electron to go through the region without being deflected. It can be calculated as :

qE=qvB\ \sin\theta

Here, \sin\theta=90^{\circ}

E=vB\\\\B=\dfrac{E}{v}\\\\B=\dfrac{10^4}{5\times 10^7}\\\\B=2\times 10^{-4}\ T

So, the magnetic field that will allow the electron to go through the region without being deflected is 2\times 10^{-4}\ T.

6 0
3 years ago
13. If you shorten the length of string by half that holds an object in rotation at the same tangential
Dmitrij [34]

13. doubles

The tension in the string corresponds to the centripetal force that holds the object in rotation, so:

T=F=m\frac{v^2}{r}

where m is the mass of the object, v is the tangential speed, and r is the distance of the object from the centre of rotation (therefore it corresponds to the length of the string). The problem tells us that the tangential speed remains the same (v), while the length of the string is halved, so r'=r/2. Therefore, the new tension in the string will be

T'=m\frac{v^2}{r'}=m\frac{v^2}{r/2}=2m\frac{v^2}{r}=2T

so, the Tension doubles.

14. Variations of centripetal forces

Both revolution and rotation refer to the rotational motion of an object, therefore they both involve the presence of a centripetal force, which keeps the object in circular motion. The only difference between the two is:

- Revolution is the circular motion of an object around a point external to the object (for instance, the motion of the Earth around the Sun)

- Rotation is the circular motion of an object around its centre, so around a point internal to the object (for instance, the rotation of the Earth around its axis)

15. Rotational speed

For a uniform object in circular motion, all the points of the object have same rotational speed. In fact, the rotational speed is defined as

\omega=\frac{\Delta \theta}{\Delta t}

where \Delta \theta is the angular displacement covered in a time interval of \Delta t. Since all the points of the wheel are coeherent (they move together), they all cover the same angular displacement in the same time, so they all have same rotational speed.

16. away from the center of the path.

The tension in the string is responsible for keeping the tin can in circular motion. Therefore, the tension in the string represents the centripetal force, and so it is directed towards the centre of the path. According to Newton's third law, the tin can exerts a force on the string which is equal in magnitude (so, same magnitude of the tension), but opposite in direction: therefore, away from the centre of the path.

17. weight of the bob.

There are two forces acting on the bob in the vertical direction: the weight of the bob (downward) and the vertical component of the string tension (upward). Since there is no acceleration along the vertical direction, the net force must be zero, so these two forces must be equal: it means that the vertical component of the string tension is equal to the weight of the bob. Along the horizontal direction, instead, the horizontal component of the string tension corresponds to the centripetal force that keeps the bob in circular motion.

18. horizontal component of string tension.

Along the horizontal direction, there is only one force acting on the bob: the horizontal component of the string tension. Since the bob is moving of circular motion along the horizontal direction, this means that this force (the horizontal component of the string tension) must correspond to the centripetal force that keeps the pendulum in circular motion.

19. inward, toward the center of swing.

The force that the can exerts on the bug is the force that keeps the bug in circular motion (since it prevents the bug from moving away). Therefore, it must corresponds to the centripetal force.

20. speed of the car. AND radius of curvature.

The normal force exerted on a car executing a turn on a banked track is given by the expression:

N=\frac{mg}{cos \theta - \mu sin \theta}

where m is the mass of the car, g is the gravitational acceleration, \theta is the angle of the bank, and \mu is the coefficient of friction.

From the formula, we see that the normal force depends on \theta (the angle of the bank) and \mu (the coefficient of friction), while it does not depend on the speed of the car or on the radius of curvature. Therefore, these two are the correct answers.

3 0
3 years ago
PLEASE ANSWER THIS ASAP!!!
Burka [1]

Answer:

I guess B

Explanation:

Because it stop by it self so that is digital

5 0
2 years ago
The net force on an object moving with constant speed in circular motion is in which direction
ipn [44]

Answer:

the net force is the same direction as the acceleration

Explanation:

so toward the center of the circle about which the object is constantly moving.

7 0
3 years ago
‏Explain how an electron emitted by the photoelectric effect can have kinetic energy less than threshold energy ?
xenn [34]

Answer:

the photons (quanta of light) collide with the electrons, these electrons have to overcome the threshold energy that is the energy of union with the metal, and the energy that remains is converted to kinetic energy.

          K = E - Ф

Explanation:

The photoelectric effect is the emission of electrons from the surface of a metal.

This was correctly explained by Einstein, in his explanation the energy of the photons (quanta of light) collide with the electrons, these electrons have to overcome the threshold energy that is the energy of union with the metal, and the energy that remains is converted to kinetic energy.

          E = hf

          E = K + Ф

          K = E - Ф

The energy of the photons is given by the Planck relation E = hf and according to Einstein the number of joints must be added

            E = n hf

Therefore, depending on the value of this energy, the emitted electrons can have energy from zero onwards.

4 0
3 years ago
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