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3 years ago

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PLEASE HELP Why should you specify a reference frame when describing motion? a. a description of motion depends on the reference

frame b. motion appears the same in all reference frames. c. reference frames affect the motion of an object. d. you can see motion better from certain reference frames.

2 answers:

Mnenie [13.5K]3 years ago

6 0

C!!!MUCH LOVE I WAS SUCK ON THAT QUESTION BUT I GOT IT SO I HAD TO TELL YOU

zysi [14]3 years ago

3 0

Answer:

its c hope this helps

Explanation:

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You are driving along the New York State Thruway in a line of cars all travelling at a constant speed of 108.5 km/hr. The car in

IgorC [24]

Answer:

Car first should be 30.13 m behind the second car.

Explanation:

Given that,

Constant speed = 108.5 Km/hr

Time = 1 sec

Let the distance covered by second car S and by first car S'

We need to calculate the distance covered by second car

Using equation of motion

$S=ut-\dfrac{1}{2}at^2$ .....(I)

The distance covered by first car to avoid collision

$S''=S'+S$

Put the value into the formula

$S'+S=ut+ut-\dfrac{1}{2}at^2$ ...(II)

We need to calculate the distance covered by first car

Using equation (I) and (II)

$S'=ut$

Put the value into the formula

$S'=108.5\times\dfrac{5}{18}\times1$

$S'=30.13\ m$

Hence, Car first should be 30.13 m behind the second car.

7 0

3 years ago

A radar gun can determine the speed of a moving automobile by measuring the difference in frequency between emitted and reflecte

kupik [55]

Answer:

Doppler effect.

Explanation:

The velocity of the moving car affects the wavelengths of the reflecting radio waves according to the principle of Doppler effect. Therefore, for a car moving away from the radar gun, the wavelength of the radio waves is increased, and for a car moving towards the gun, the wavelength is decreased. The degree of increase or decreases depends on the speed of the car, so if you know how much a wavelength has changed, you know the velocity of the car.

4 0

3 years ago

Two vectors, r and c, are equal: r = c. Which of the following statements are true? (Select all that apply.)

s344n2d4d5 [400]

Answer:

(A) The y-component of r must be equal to the y-component of c

(B) The x-component of r must be equal to the x-component of c

(C) The z-component of r must be equal to the z-component of c

(F) The unit vector r must be equal to the unit vector c.

Explanation:

If two vectors are equal there are some conditions must be satisfy for the two vectors to be equal.

Let us suppose 2 vectors as,

$A=a_{1}i+ a_{2}j+a_{3}k$ and

$B=b_{1}i+ b_{2}j+b_{3}k$

The conditions for the above two vectors should be equal are:

(1) $a_{1}=b_{1}$ , $a_{2}=b_{2}$ , and $a_{3}=b_{3}$ .

(2) Unit vector of A must be equal to unit vector of B.

(3) Magnitude of both the vectors should be equal.

Now, according to question and observing above conditions of equality for r and c to be equal, the statements should be true are:

(A) The y-component of r should be equal to the y-component of c

(B) The x-component of r should be equal to the x-component of c

(C) The z-component of r should be equal to the z-component of c

(F) The unit vector r should be equal to the unit vector c.

6 0

3 years ago

A 1.2 kg basketball is thrown upwards. What is the potential energy of the basketball at the top of its path if it reaches a hei

Dahasolnce [82]

Answer:

Answer is 183.6 J

Explanation:

Using the Physics reference sheet the formula for Potential energy is

(mass) x (gravity) x (height)

Mass= 1.2

Gravity I used is 9.81 (use 10 to get the answer most schools use)

Height= 15.6

5 0

3 years ago

I place an ice cube with a mass of 0.223 kg and a temperature of −35◦C is placed into an insulated aluminum container with a mas

Nadya [2.5K]

To solve this problem it is necessary to use the calorimetry principle. From the statement it asks about the remaining ice, that is, to the point where the final temperature is 0 ° C.

We will calculate the melted ice and in the end we will subtract the total initial mass to find out how much mass was left.

The amount of heat transferred is defined by

$Q = mc\Delta T$

Where,

m = mass

c = Specific heat

$\Delta T =$ Change in temperature

There are two states, the first is that of heat absorbed by that mass 'm' of melted ice and the second is that of heat absorbed by heat from -35 ° C until 0 ° C is reached.

Performing energy balance then we will have to

$Q_i-E_h = Q_m$

Where,

$Q_ i$ = Heat absorbed by whole ice

$Q_m$ = Heat absorbed by mass

$E_h$ = Heat energy by latent heat fusion/melting

$m_i*c_i \Delta T +m*L_f = (m_wc_w+m_{al}c_{al})\Delta T$

Replacing with our values we have that

$0.223*2108(-(-35))+m*3.34*10^5 = (0.452*4186+0.553*902)(27-0)$

$16452.9+334000m = (1892.072+498.806)*27$

Rearrange and find m,

$m = 0.144Kg$

Therefore the Ice left would be

$m' = 0.223-0.144$

$m' = 0.079Kg$

Therefore there is 0.079kg ice in the containter when it reaches equilibrium

8 0

4 years ago