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umka2103 [35]
2 years ago
14

If interstellar gas has a density of 1 atom/cm3, how big a volume of material must be used to make a star with the mass of the S

un
Physics
1 answer:
Yuki888 [10]2 years ago
7 0

The volume of the material that must be used to make a star with the mass of the sun is 1.2×10⁵¹ m³.

<h3>What is volume?</h3>

Volume is the amount of space occupied by an object or a plane figure.

To calculate the volume of the material that must be used to make a star with the mass of the sun, we use the formula below.

Formula:

  • D = m/V............ Equation 1

Where:

  • D = Density of the interstellar gas
  • m = mass of the sun
  • V = Volume of the material

Make V the subject of the equation

  • V = m/D........... Equation 2

From the question,

Given:

  • m = mass of the sun = 1.9891×10³⁰ kg
  • D = 1 atom/cm³ = 1.66×10⁻²¹ kg/m³

Substitute these values into equation 2

  • V = ( 1.9891×10³⁰)/(1.66×10⁻²¹)
  • V = 1.2×10⁵¹ m³

Hence, The volume of the material that must be used to make a star with the mass of the sun is 1.2×10⁵¹ m³.

Learn more about volume here: brainly.com/question/1972490

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Ans: Thus, the kinetic energy change = 4.5 J

The mass of puppy = 3kg

Kinetic energy initial = \frac{1}{2} mv^{2}
                                   = \frac{1}{2}*3*4 = 6 kg-m/s2

Kinetic energy final = \frac{1}{2} mv^{2} = \frac{1}{2}*3*1 = 1.5 kg-m/s2

Thus, the kinetic energy change = 4.5 J
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4 years ago
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An isolated charged point particle produces an electric field with magnitude E at a point 2 m away. At a point 1 m from the part
guajiro [1.7K]

Explanation:

The electric field at a distance r from the charged particle is given by :

E=\dfrac{kq}{r^2}

k is electrostatic constant

if r = 2 m, electric field is given by :

E_1=\dfrac{kq}{(2)^2}\\\\=\dfrac{kq}{4}\ .....(1)

If r = 1 m, electric field is given by :

E_2=\dfrac{kq}{r_2^2}\\\\=\dfrac{kq}{1}\ ....(2)

Dividing equation (1) and (2) we get :

\dfrac{E_1}{E_2}=\dfrac{\dfrac{kq}{4}}{kq}\\\\\dfrac{E_1}{E_2}=\dfrac{1}{4}\\\\E_2=4\times E_1

So, at a point 1 m from the particle, the electric field is 4 times of the electric field at a point 2 m.

4 0
3 years ago
Which force best represents Fg
kiruha [24]

Answer:

The weight of barbell acting on a weight lifter is 80N.

Explanation:

6 0
3 years ago
2. A baseball player throws a ball a distance of 45.0 m at a speed of 30.0 m/s. How long is the
madreJ [45]

Answer:

v = d/t

30.0m/s = 45.0m / t

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3 years ago
The mass of the Sun is 2 × 1030 kg, the mass of the Earth is 6 × 1024 kg, and their center-to-center distance is 1.5 × 1011 m. S
choli [55]

Answer:

0.00461031264 m/s

Explanation:

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

M = Mass of the Earth =  6 × 10²⁴ kg

r = Distance between Earth and Sun = 1.5\times 10^{11}\ m

t = Time taken = 3 days

Acceleration is given by

a=\dfrac{GM}{r^2}\\\Rightarrow a=\dfrac{6.67\times 10^{-11}\times 6\times 10^{24}}{(1.5\times 10^{11})^2}\\\Rightarrow a=1.77867\times 10^{-8}\ m/s^2

Velocity of the star

v=u+at\\\Rightarrow v=0+1.77867\times 10^{-8}\times 3\times 24\times 60\times 60\\\Rightarrow v=0.00461031264\ m/s

The Sun's speed will be 0.00461031264 m/s

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3 years ago
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