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umka2103 [35]
1 year ago
14

If interstellar gas has a density of 1 atom/cm3, how big a volume of material must be used to make a star with the mass of the S

un
Physics
1 answer:
Yuki888 [10]1 year ago
7 0

The volume of the material that must be used to make a star with the mass of the sun is 1.2×10⁵¹ m³.

<h3>What is volume?</h3>

Volume is the amount of space occupied by an object or a plane figure.

To calculate the volume of the material that must be used to make a star with the mass of the sun, we use the formula below.

Formula:

  • D = m/V............ Equation 1

Where:

  • D = Density of the interstellar gas
  • m = mass of the sun
  • V = Volume of the material

Make V the subject of the equation

  • V = m/D........... Equation 2

From the question,

Given:

  • m = mass of the sun = 1.9891×10³⁰ kg
  • D = 1 atom/cm³ = 1.66×10⁻²¹ kg/m³

Substitute these values into equation 2

  • V = ( 1.9891×10³⁰)/(1.66×10⁻²¹)
  • V = 1.2×10⁵¹ m³

Hence, The volume of the material that must be used to make a star with the mass of the sun is 1.2×10⁵¹ m³.

Learn more about volume here: brainly.com/question/1972490

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UkoKoshka [18]

Answer:

Mass as a Measure of the Amount of Inertia

All objects resist changes in their state of motion. All objects have this tendency - they have inertia.

Explanation:

hope this helps

5 0
2 years ago
If the maximum tension in the simulation is 10.0 N, what is the linear mass density (m/L) of the string
vovikov84 [41]

Complete Question

The speed of a transverse wave on a string of length L and mass m under T is given by the formula

     v=\sqrt{\frac{T}{(m/l)}}

If the maximum tension in the simulation is 10.0 N, what is the linear mass density (m/L) of the string

Answer:

(m/l)=\frac{10}{V^2}

Explanation:

From the question we are told that

Speed of a transverse wave given by

v=\sqrt{\frac{T}{(m/l)}}

Maximum Tension is T=10.0N

Generally making (m/l) subject from the equation mathematically we have

v=\sqrt{\frac{T}{(m/l)}}

v^2=\frac{T}{(m/l)}

(m/l)=\frac{T}{V^2}

(m/l)=\frac{10}{V^2}

Therefore the Linear mass in terms of Velocity is given by

(m/l)=\frac{10}{V^2}

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3 years ago
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Answer:

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Explanation:

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3 years ago
Dams hold collected water back from flowing at their normal rate. What type of energy is in the collected water above the dam? c
Andreyy89
It would be mechanical potential energy.
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At what distance will the weight of a body be halved , Earth's radius=6.4×10^6
Sholpan [36]

A body of mass m has weight

F = GMm/r²

on the surface of the Earth, where G is the universal gravitational constant, M is the mass of the Earth, and r is it's radius.

If the weight is to be halved, then we have

1/2 F = 1/2 GMm/r² = (1/√2)² GMm/r² = GMm/(√2 r²)

so the distance between the body and the planet's center needs to be

√2 × 6.4 × 10⁶ m ≈ 9.1 × 10⁶ m

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2 years ago
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