Question

In a double-slit experiment, the third-order maximum for light of wavelength 480 nmnm is located 17 mmmm from the central bright spot on a screen 1.6 mm from the slits. Light of wavelength 670 nmnm is then projected through the same slits. Part A How far from the central bright spot will the second-order maximum of this light be located

Answer 1

Answer:

0.126mm

Explanation:

To find the distance to the central bright spot you can use the following formula:

$y=\frac{m\lambda D}{d}$

y: distance from the m-bright spot to the central one.

m: order of the bright (in this case, the second order, m=2)

D: distance to the scree = 1.6m

d: distance between slits = 17mm = 17*10^{-3}m

By replacing the values of m, D, d and the wavelength you obtain:

$y=\frac{(2)(670*10^{-9}m)(1.6m)}{(17*10^{-3}m)}=1.26*10^{-4}m=0.126mm$

hence, the ditance from the second order fringe to the central spot is 0.126mm