First of all, I'm going to assume that we have a concave down parabola, because the stream of water is subjected to gravity.
If we need the vertex to be at
, the equation will contain a
term.
If we start with
we have a parabola, concave down, with vertex at
and a maximum of 0.
So, if we add 7, we will translate the function vertically up 7 units, so that the new maximum will be ![(4, 7)](https://tex.z-dn.net/?f=%20%284%2C%207%29%20)
We have
![y = -(x-4)+7](https://tex.z-dn.net/?f=%20y%20%3D%20-%28x-4%29%2B7%20)
Now we only have to fix the fact that this parabola doesn't land at
, because our parabola is too "narrow". We can work on that by multiplying the squared parenthesis by a certain coefficient: we want
![y = a(x-4)^2+7](https://tex.z-dn.net/?f=%20y%20%3D%20a%28x-4%29%5E2%2B7%20)
such that:
Plugging these values gets us
![0 = a(8-4)^2+7 \iff 16a+7=0 \iff a = -\dfrac{7}{16}](https://tex.z-dn.net/?f=%200%20%3D%20a%288-4%29%5E2%2B7%20%5Ciff%2016a%2B7%3D0%20%5Ciff%20a%20%3D%20-%5Cdfrac%7B7%7D%7B16%7D)
As you can see in the attached figure, the parabola we get satisfies all the requests.
Answer:
y=-2/3 x +4
Step-by-step explanation:
slop = (6-0)/(-3-6)= -2/3
c= 4 (when x =0)
line equation:
y= mx + c
y=-2/3 x +4
Answer:
the sequence is arithmetic with first term 2 and common different is 2
Step-by-step explanation:
please give me brainlest
Answer:
I'm pretty sure it is 0.4
Step-by-step explanation:
I really hope this helps