To find the area of a quarter circle, you simply take a quarter of a full circle. As all quarters are equal, this means that the formula would be <span><span>π<span><span>r2</span>4</span></span><span>π<span><span>r2</span>4</span></span></span><span>. But wait, there's more. If you notice, </span><span><span>π<span><span>r2</span>4</span>=π<span><span>r2</span>2</span></span><span>π<span><span>r2</span>4</span>=π<span><span>r2</span>2</span></span></span><span>. This coincides with the circle formula, just with half the radius. Notice anything? A quarter of a circle can be calculated in the same way a circle a quarter the size can. This means that a quarter circle is equal to a circle a quarter size. In this same way, a ninth of a circle is equal to a circle of one ninth the size.</span>
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▹ Answer
You can use a graphing calculator.
▹ Step-by-Step Explanation
Attached is a screenshot.
Hope this helps!
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Answer:
3rd option
Step-by-step explanation:
( factorise numerator and denominator )
3x² - 3 ← factor out 3 from each term
= 3(x² - 1²) ← x² - 1 is a difference of squares and factors in general as
a² - b² = (a - b)(a + b)
x² - 1
= x² - 1²
= (x - 1)(x + 1) , then
3x² - 3 = 3²(x - 1)(x + 1) ← in factored form
--------------------------------
x² - 5x + 4
consider the factors of the constant term (+ 4) which sum to give the coefficient of the x- term (- 5)
the factors are - 1 and - 4 , since
- 1 × - 4 = + 4 and - 1 - 4 = - 5 , then
x² - 5x + 4 = (x - 1)(x - 4)
then
= ← in factored form
Answer:
He showed that f(n) ÷ f(n - 1) was a constant ratio.
Given that Jake has proved that a function f(x) is a geometric sequence.
GEOMETRIC SEQUENCE: A geometric sequence is a sequence of numbers where each term is found by multiplying the preceding term by a constant called the common ratio, r.
So, in Jame's proof, he showed that each term is multiplied by a constant to get the next term.
That is, if 'c' is the constant that was used in the proof, then we must have
This implies that
Therefore, he showed that f(n) ÷ f(n - 1) was a constant ratio.