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Ahat [919]
2 years ago
15

Find cos(α) in the triangle.

Mathematics
2 answers:
ki77a [65]2 years ago
8 0
<h3><u>Ⲁⲛ⳽ⲱⲉⲅ</u><u>:</u></h3>

\quad\hookrightarrow\quad \sf { \dfrac{35}{37} }

<h3><u>Ⲋⲟⳑⳙⲧⳕⲟⲛ :</u></h3>

In the given triangle , for angle α , we have :

  • Base = 35
  • Hypotenuse = 37
  • Perpendicular = 12

And, cos α for a right angled triangle is the ratio of the adjacent side to the hypotenuse, where α is the acute angle ,i.e:

\quad\longrightarrow\quad {\pmb{\sf {cos\:\alpha = \dfrac{Base}{Hypotenuse} }}}

<u>Therefore:</u>

\implies\quad \tt { cos\:\alpha = \dfrac{B}{H} }

\implies\quad \tt\underline{ \underline{\pmb{{cos\:\alpha =\dfrac{35}{37}} }}}

vesna_86 [32]2 years ago
3 0

Answer:

.............................................

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Solve for y.<br> 2x-3y=9
cluponka [151]

Answer:

y = 2/3x - 3

Step-by-step explanation:

Step 1: Write equation

2x - 3y = 9

Step 2: Solve for <em>y</em>

  1. Subtract 2x on both sides: -3y = 9 - 2x
  2. Divide both sides by -3: y = -3 + 2/3x
  3. Rewrite: y = 2/3x - 3
6 0
3 years ago
The solution set for an inequality is graphed on this number line which numbers below belong to the solution set of the inequali
Rudiy27

Answer:

B, C E and F

Step-by-step explanation:

The inequality is x > -30

the numbers belonging to the solution are all on the heavy line.

Note -30 is not included because of the clear circle on -30

also -44 is not on the heavy line.


7 0
3 years ago
&lt;5 is a supplementary of &lt;6 , and m&lt;5=78 , find m&lt;6
irakobra [83]

Answer:

m<6 is 102°

Step-by-step explanation:

Angles that are supplementary are equal to a total of 180°.

Subtract the 78 from the 180 to find your answer.

180-78=102

3 0
3 years ago
Solve for x. enter your answer in interval notation using grouping symbols. x^2+15x&lt;-36
Oliga [24]
X²+15x+36<0

at first solve quadratic equation

D=b²-4ac= 225-4*1*36= 81

x=(-b+/-√D)/2a
x=(-15+/-√81)/2= (-15+/-9)/2
x1=(-15-9)/2=-12
x2=(-15+9)/2=-3

we can write x²+15x+36<0 as (x+12)(x+3)<0

(x+12)(x+3)<0 can be 2 cases, because for product to be negative one factor should be negative , and second factor should be positive
 1 case)      x+12<0, and x+3>0,                                            
                       x<-12, and x>-3
(-∞, -12) and(-3,∞) gives empty set

or second case)  x+12>0 and x+3<0
x>-12 and x<-3
(-12,∞) and (-∞,-3)  they are crossing , so (-12, -3)  is a solution of this inequality


3 0
3 years ago
ASAP!! Please help me. I will not accept nonsense answers, but will mark as BRAINLIEST if you answer is correctly with solutions
stiv31 [10]

Answer:

last option

Step-by-step explanation:

It will take 200 / 5 = 40 months for Sara's phone to lose all its value, therefore, the domain is 0 ≤ t ≤ 40 because you can't have negative months. Since negative money is not a thing, the range has to be 0 ≤ V(t) ≤ 200 because it stops at 0 and starts at 200.

8 0
3 years ago
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