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pashok25 [27]
3 years ago
12

A pulley system used to lift car tires has a mechanical advantage of 11.2. If you pull on the pulley with a force of 150 N, how

much force does the pulley exert on the tire?
Physics
2 answers:
Novay_Z [31]3 years ago
7 0
1680 is the answer i got because i did this problem in apex
IgorC [24]3 years ago
5 0

Answer:

Load = 1680 N

Explanation:

Mechanical advantage of the pulley system, MA = 11.2

If a person pull on a pulley with a force of 150 N we have to find the amount of force the pulley exert on the tire. Mechanical advantage of a pulley system is given by the ratio of load to the effort force i.e.

IMA=\dfrac{load}{effort}

11.2=\dfrac{load}{150\ N}

Load = 1680 N

Hence, the force the pulley exert on the tire is 1680 Newtons.

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Kenetic energy increasing because velocity increased
Ymorist [56]

Answer:

Explanation:

The formula for kinetic energy  Ke=1/2mv^2 where Ke is kinetic energy, m=mass, and v= velocity.

If the kinetic energy is increased that means that there must be an increase in mass or velocity. However, since the velocity is squared that means that velocity affects the kinetic energy of the object more than the mass does.

5 0
3 years ago
A box of mass 20kg is pulled up an inclined plane by a force of 285N. Given that the value of the incline angle is 30 degrees an
docker41 [41]

Given :

Mass of box , m = 250 kg.

Force applied , F = 285 N.

The value of the incline angle is 30°.

the coefficient of dynamic friction is \mu=0.72 .

To Find :

The speed with which the box is moving with, assuming it takes 4 seconds to reach the top of the incline.

Solution :

Net force applied in box is :

F=285 - mgsin\ \theta - \mu mg cos \ \theta\\ \\F=285-mg( sin \ \theta - \mu cos\ \theta)\\\\F=285 - 20\times 10( \dfrac{1}{2}+0.72\times \dfrac{\sqrt{3}}{2})\\\\F=60.29\ N

Acceleration , a=\dfrac{F}{m}=\dfrac{60.29}{20}=3.01\ m/s^2.

By equation of motion :

v=u+at\\\\v=0+3.01\times 4\\\\v=12.04\ m/s

Therefore, the speed of box is 12.04 m/s.

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3 years ago
A proton and an electron are released from rest in the center of a capacitor.
Sunny_sXe [5.5K]

Answer:

a)  equal 1, b) less than 1

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Electron

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If we do not take into account the sign the relationship is equal to one (1)

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The mass of the proton much greater than the mass of the electron

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          ae = - q E /  m_{e}

          ap / ae =  m_{e} /  m_{p} =  m_{e}/1600  m_{e} =1/1600

 It is much smaller than 1

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