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Pavel [41]
3 years ago
9

A proton and an electron are released from rest in the center of a capacitor.

Physics
1 answer:
Sunny_sXe [5.5K]3 years ago
7 0

Answer:

a)  equal 1, b) less than 1

Explanation:

a) the electric force is given by

         Fe = q E

The charge of the electron and proton has the same value, that of the proton is positive and that of the electron is negative

Proton

        Fp = qE

Electron

         Fe = - q E

         Fp / Fe = -1

If we do not take into account the sign the relationship is equal to one (1)

b) to calculate the force we use Newton's second law

           F = ma

           qE = m a

           a = q E / m

The mass of the proton much greater than the mass of the electron

          ap = q E / m_{p}

          ae = - q E /  m_{e}

          ap / ae =  m_{e} /  m_{p} =  m_{e}/1600  m_{e} =1/1600

 It is much smaller than 1

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A woman does 236 J of work
Ratling [72]

Answer:

The woman's force was directed 59.22⁰ to the horizontal.

Explanation:

Given;

work done by the woman, W = 236 J

distance through the load was moved, d = 24.4 m

applied force, F = 18.9 N

inclination of the force, = θ

The work done by the woman is calculated as;

W = Fdcosθ

cos \ \theta = \frac{W}{Fd} \\\\cos \ \theta = \frac{236 }{18.9 \times 24.4} \\\\cos \ \theta =  0.5118\\\\\theta = cos^{-1} ( 0.5118)\\\\\theta =59.22^0

Therefore, the woman's force was directed 59.22⁰ to the horizontal.

8 0
3 years ago
Energy of a SpacecraftVery far from earth(at R=\infty), a spacecraft has run out of fuel and its kineticenergy is zero. If only
Firdavs [7]

Answer:

s_e=\sqrt{\frac{2GM_e}{R_e^2}}

Explanation:

In this case mechanical energy is conserved, which means that the sum of the initial kinetic energy and initial potential gravitational energy will be equal to the sum of the final kinetic energy and final potential gravitational energy:

K_i+U_i=K_f+U_f

Which in our case will be:

\frac{mv_i^2}{2}+\frac{-GM_em}{r_i^2}=\frac{mv_f^2}{2}+\frac{-GM_em}{r_f^2}

Which, since v_i=0m/s, r_i=infinity, r_f=R_e, v_f=s_e and canceling <em>m</em> means that:

\frac{s_f^2}{2}=\frac{GM_e}{R_e^2}

Solving for the final velocity we get:

s_e=\sqrt{\frac{2GM_e}{R_e^2}}

6 0
3 years ago
How fast must a 1000 kg car be moving to have a kinetic energy of 2.0*10^3
lawyer [7]
Kinetic Energy is defined by Ke=1/2mv^2. Plug in and solve for v.

2,000 = 1/2(1000)(v)^2
4=(v)^2
v=2 m/s

The car must move at 2 m/s to have a Ke of 2,000 Joules.
6 0
3 years ago
A 57 kg skier starts from rest at a height of H = 27 m above the end of the ski-jump ramp. As the skier leaves the ramp, his vel
Hatshy [7]

Answer:

(a)h=5.95m

(b) h is the same

Explanation:

According to the law of conservation of energy:

E_i=E_f\\U_i+K_i=U_f+K_f

The skier starts from rest, so K_i=0 and we choose the zero point of potential energy in the end of the ramp, so U_f=0. We calculate the final speed, that is, the speed when the skier leaves the ramp:

mgH=\frac{mv^2}{2}\\v=\sqrt{2gH}\\v=\sqrt{2(9.8\frac{m}{s^2})(27m)}\\v=23\frac{m}{s}

Finally, we calculate the maximum height h above the end of the ramp:

v_f^2=v_i^2-2gh\\

The initial vertical speed is given by:

v_i=vsin\theta

and the final speed is zero, solving for h:

h=\frac{v_i^2}{2g}\\h=\frac{((23\frac{m}{s})sin(28^\circ))^2}{2(9.8\frac{m}{s^2})}\\h=5.95m

(b) We can observe that the height reached does not depend on the mass of the skier

3 0
4 years ago
Water flows over a section of Niagara Falls at the rate of 1.2×106 kg/s and falls 50.0 m. How much power is generated by the fal
quester [9]

Answer:

5.88×10⁸ W

Explanation:

Power = energy / time

P = mgh / t

P = (m/t) gh

P = (1.2×10⁶ kg/s) (9.8 m/s²) (50.0 m)

P = 5.88×10⁸ W

7 0
3 years ago
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