Question

A proton and an electron are released from rest in the center of a capacitor.

Answer 1

Answer:

a)  equal 1, b) less than 1

Explanation:

a) the electric force is given by

         Fe = q E

The charge of the electron and proton has the same value, that of the proton is positive and that of the electron is negative

Proton

        Fp = qE

Electron

         Fe = - q E

         Fp / Fe = -1

If we do not take into account the sign the relationship is equal to one (1)

b) to calculate the force we use Newton's second law

           F = ma

           qE = m a

           a = q E / m

The mass of the proton much greater than the mass of the electron

          ap = q E / $m_{p}$

          ae = - q E /  $m_{e}$

          ap / ae =  $m_{e}$ /  $m_{p}$ =  $m_{e}$/1600  $m_{e}$ =1/1600

 It is much smaller than 1