Kenetic energy increasing because velocity increased
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Consult the attached free body diagram.
By Newton's second law, the net force on the crate acting parallel to the surface is
∑ F[para] = (370 N) cos(-20°) - f = 0
(this is the x-component of the resultant force)
where
• (370 N) cos(-20°) = magnitude of the horizontal component of the pushing force
• f = magnitude of kinetic friction
The crate is moving at a constant speed and thus not accelerating, so the crate is in equilibrium.
Solve for f :
f = (370 N) cos(-20°) ≈ 347.686 N
The net force acting perpendicular to the surface is
∑ F[perp] = n - 1480 N - (370 N) sin(-20°) = 0
(this is the y-component of the resultant force)
where
• n = magnitude of normal force
• 1480 N = weight of the crate
• (370 N) sin(-20°) = magnitude of the vertical component of push
The crate doesn't move up or down, so it's also in equilibrium in this direction.
Solve for n :
n = 1480 N + (370 N) sin(-20°) ≈ 1606.55 N ≈ 1610 N
Then the coefficient of kinetic friction is µ such that
f = µn ⇒ µ = f/n ≈ 0.216
Explanation:
The given data is as follows.
Temperature of metal = = (296 + 273) K
= 569 K
Density of the metal = 8.85 =
(as
)
Atomic mass = 51.40 g/mol
Vacancies =
Formula to calculate the number of atomic sites is as follows.
n =
=
=
Now, we will calculate the energy as follows.
E =
where, K =
E =
=
Therefore, we can conclude that energy (in eV/atom) for vacancy formation in given metal, M, is .