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ioda
2 years ago
9

A massless rope passes over a massless pulley suspended from the ceiling. A 4-kg block is attached to one end and a 5-kg block i

s attached to the other end. The acceleration of the 5-kg block is
Physics
1 answer:
borishaifa [10]2 years ago
4 0

The acceleration on the 5kg block is 1.088m/s^2

Data;

  • mass(a) = 4kg
  • mass (b) = 5kg
  • acceleration of the 5kg block.
<h3>The Acceleration on the 5kg block</h3>

To solve this question, we just need to use Newton's second law of motion which states that "the time rate of change of the momentum of a body is equal in both magnitude and direction to the force imposed on it."

F_n_e_t = M_t_o_t_a_l * a\\F = ma\\F_n_e_t = mg\\

But then the force on both sides will be

mg = ma\\5g - 4g= (4+5) a\\(5-4)g = 9a\\g = 9a\\a = \frac{g}{9} \\a = \frac{9.80}{9} \\a = 1.088 m/s^2

The acceleration on the 5kg block is 1.088m/s^2

Learn more on newton's second law of motion here;

brainly.com/question/3050695

brainly.com/question/13447525

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1 2 3 4 5 6 7 8 9 10
7nadin3 [17]

Answer:

<h2>C. <u>0.55 m/s towards the right</u></h2>

Explanation:

Using the conservation of law of momentum which states that the sum of momentum of bodies before collision is equal to the sum of the bodies after collision.

Momentum = Mass (M) * Velocity(V)

BEFORE COLLISION

Momentum of 0.25kg body moving at 1.0m/s = 0.25*1 = 0.25kgm/s

Momentum of 0.15kg body moving at 0.0m/s(body at rest) = 0kgm/s

AFTER COLLISION

Momentum of 0.25kg body moving at x m/s = 0.25* x= 0.25x kgm/s

<u>x is the final velocity of the 0.25kg ball</u>

Momentum of 0.15kg body moving at 0.75m/s(body at rest) =

0.15 * 0.75kgm/s = 0.1125 kgm/s

Using the law of conservation of momentum;

0.25+0 = 0.25x + 0.1125

0.25x = 0.25-0.1125

0.25x = 0.1375

x = 0.1375/0.25

x = 0.55m/s

Since the 0.15 kg ball moves off to the right after collision, the 0.25 kg ball will move at <u>0.55 m/s towards the right</u>

<u></u>

4 0
3 years ago
Which of the following statements describe the transfer of energy a. Collision of atoms causing nuclear reactions B. A car speed
oksano4ka [1.4K]
I think the answer would be A.
8 0
3 years ago
Standing waves are set up on two strings fixed at each end, as shown in the drawing. The two strings have the same tension and m
uysha [10]

The beat frequency produced by the two standing waves is 13 Hz.

<h3>The wavelength of the shorter string</h3>

The wavelength of the shorter string is calculated as follows;

L = \frac{\lambda}{2} \\\\\lambda = 2L\\\\\lambda = \frac{v}{f} \\\\\lambda = \frac{41.9}{225} \\\\\lambda = 0.186 \ m\\\\\lambda = 18.6 \ cm\\\\L= \frac{\lambda }{2} \\\\L = \frac{18.6 \ cm}{2} = 9.3\ cm

<h3>The length of the longer string</h3>

L_2 = 0.58 \ cm \ + 9.3 \ cm\\\\L_2 = 9.88 \ cm \\\\\lambda _2 = 2L_2\\\\\lambda _2 = 2(9.88 \ cm)\\\\\lambda_2 = 19.76 \ cm = 0.1976 \ m

The frequency of the longer string is calculated as follows;

v_1 = v_2\\\\f_2 = \frac{v_2}{\lambda_2} \\\\f_2 = \frac{41.9}{0.1976} \\\\f_2 = 212 \ Hz

<h3>Beat frequency</h3>

The beat frequency produced by the two standing waves is calculated as follows;

F_b = 225 \ Hz \ - \ 212 \ Hz\\\\F_b = 13 \ Hz

Learn more about beat frequency here: brainly.com/question/3086912

8 0
3 years ago
A vehicle that goes from 5 m/s to 45 m/s in 8 s. What is its acceleration?
WINSTONCH [101]

Answer:

5

Explanation:

a= v ÷ t which when you insert it into the equation it should be a= 40m/s ÷ 8s

7 0
2 years ago
A circular saw blade with radius 0.175 m starts from rest and turns in a vertical plane with a constant angular acceleration of
ANEK [815]

Answer:

The distance the piece travel in horizontally axis is

L=3.55m

Explanation:

a=2 \frac{rev}{s^{2}} \\h=0.820m\\r = 0.125 m&#10;\\d=150rev

d= 155 rev = 155(2\pi ) = 310\pi rad

a= 2.0 \frac{rev}{s^{2} } = 2.0(2\pi )  = 4.0\pi \frac{rev}{s^{2} }

d=d_{i}+vo*t+\frac{1}{2}*a*t^{2} \\ di=0\\vo=0\\d=\frac{1}{2}*a*t^{2}\\t=\sqrt{\frac{2*d}{a}}\\t=\sqrt{\frac{2*310 rad}{4\frac{rad}{s^{2}}}} \\t=12.449

w=a*t\\w=4\frac{rad}{s^{2}}*12.449s\\ w=49.79 \frac{rad}{s}

Now the angular velocity is the blade speed so:

V=w*r\\V=49.79 \frac{rad}{s}*0.175m\\V=8.7 \frac{m}{s}

assuming no air friction effects affect blade piece:

time for blade piece to fall to floor

t=\sqrt{\frac{2*h}{g}}\\t=\sqrt{\frac{2*0.820m}{9.8\frac{m}{s^{2} } }}\\t=0.409s

Now is the same time the piece travel horizontally

L=t*V\\L=0.409s*8.7\frac{m}{s}\\L=3.55m

blade piece travels  HORIZONTALLY = (24.5)(0.397) = 9.73 m  ANS

6 0
4 years ago
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