Answer:
<h2>C. <u>
0.55 m/s towards the right</u></h2>
Explanation:
Using the conservation of law of momentum which states that the sum of momentum of bodies before collision is equal to the sum of the bodies after collision.
Momentum = Mass (M) * Velocity(V)
BEFORE COLLISION
Momentum of 0.25kg body moving at 1.0m/s = 0.25*1 = 0.25kgm/s
Momentum of 0.15kg body moving at 0.0m/s(body at rest) = 0kgm/s
AFTER COLLISION
Momentum of 0.25kg body moving at x m/s = 0.25* x= 0.25x kgm/s
<u>x is the final velocity of the 0.25kg ball</u>
Momentum of 0.15kg body moving at 0.75m/s(body at rest) =
0.15 * 0.75kgm/s = 0.1125 kgm/s
Using the law of conservation of momentum;
0.25+0 = 0.25x + 0.1125
0.25x = 0.25-0.1125
0.25x = 0.1375
x = 0.1375/0.25
x = 0.55m/s
Since the 0.15 kg ball moves off to the right after collision, the 0.25 kg ball will move at <u>0.55 m/s towards the right</u>
<u></u>
The beat frequency produced by the two standing waves is 13 Hz.
<h3>The wavelength of the shorter string</h3>
The wavelength of the shorter string is calculated as follows;

<h3>The length of the longer string</h3>

The frequency of the longer string is calculated as follows;

<h3>Beat frequency</h3>
The beat frequency produced by the two standing waves is calculated as follows;

Learn more about beat frequency here: brainly.com/question/3086912
Answer:
5
Explanation:
a= v ÷ t which when you insert it into the equation it should be a= 40m/s ÷ 8s
Answer:
The distance the piece travel in horizontally axis is
L=3.55m
Explanation:





Now the angular velocity is the blade speed so:
assuming no air friction effects affect blade piece:
time for blade piece to fall to floor

Now is the same time the piece travel horizontally

blade piece travels HORIZONTALLY = (24.5)(0.397) = 9.73 m ANS