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-BARSIC- [3]
3 years ago
8

2) Weight & Mass : what is the difference between the two? What does it mean to be weightless

Physics
1 answer:
Lady bird [3.3K]3 years ago
4 0

The weight of an object is a measure of the force exerted on the object by gravity, or the force needed to support it whereas mass is the amount of matter contained in a body. The SI unit of weight is Newton whereas the SI unit of mass is Kilogram.

No idea about weightless maybe the objects not apparently acted on by gravity.

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A block of height 120mm is placed on top of another block with a height of 1.50 m. What is the height of the two blocks together
pav-90 [236]
We will first convert all units to meters and then solve the problem.
We are given that:
1000 mm = 1 m
120 mm = ?? meters
using cross multiplication:
120 mm = (120*1) / 1000 = 0.12 m

Now, when the two objects are placed over each other, their total height is the result of summation of both heights, therefore:
total height = 0.12 + 1.5 = 1.62 m

Based on the above calculations, the correct choice is:
<span>b) 1.62 m </span>
6 0
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You have 2 objects flying towards you. One of them is havier with lower velocity and the other one is lighter but has higher vel
Lerok [7]

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3 years ago
Estimate the theoretical fracture strength of a brittle material if it is known that fracture occurs by the propagation of an el
julia-pushkina [17]
The solution as per the attached photo.

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4 years ago
Where was the most recent earthquake closest to Berwyn, PA? Give some details.
Vadim26 [7]
11/23/2012 - 2.2 mag, 5.0mi depth 1.0875 mi from <span>Gloucester Township, NJ
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7 0
3 years ago
Read 2 more answers
The combined focal length of two thin lens is 24 cm and the focal length of one converging lens is 8
qwelly [4]

Answer: f = -12 cm

Explanation: <u>Combined</u> <u>lenses</u> is an array of  simple lenses with a common axis. The combination is useful for correction of optical aberrations which cannot be corrected by simple lenses.

When two lenses are in contact and are thin, focal lengths are related as:

\frac{1}{F} =\frac{1}{f_{1}} +\frac{1}{f_{2}}

If there is a distance between the lenses, the focal length will be:

\frac{1}{F} =\frac{1}{f_{1}} +\frac{1}{f_{2}} -\frac{d}{f_{1}f_{2}}

Since the lenses in the question above are thin and in contact, the focal length of one of them will be:

\frac{1}{F} =\frac{1}{f_{1}} +\frac{1}{f_{2}}

\frac{1}{f_{2}} =\frac{1}{f_{1}} -\frac{1}{F}

\frac{1}{f_{2}} =\frac{1}{8} -\frac{1}{24}

\frac{1}{f_{2}} =\frac{-2}{24}

f_{2}= -12

The focal length of the other lens is -12 cm, with the negative sign meaning it's a converging lens.

7 0
3 years ago
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