All categories

2 years ago

Giving brainlyist to the first person to answer with a complete and correct answer.

Mathematics

2 answers:

AURORKA [14]2 years ago

8 0

Answer:

C. 6 placemats

Step-by-step explanation:

Mindy has 200 feet of ribbon and each placemat requires 30 feet of ribbon.

Now, we need to divide 200 by 30.

200/30 ≈ 6.66666666667

Now, what whole number is before 6.66666666667?

Now, what whole number is after 6.66666666667?

What is 7 x 30?

210.

What is 6 x 30?

180.

Mindy has only 200 feet of ribbon, so she can't make 7 placements because 200 < 210, but she can make 6 placements because 200 > 180.

julsineya [31]2 years ago

3 0

Hi There!

Given:

A placemat requires 30 feet of ribbon
Mandy has 200 feet of ribbon

To Find:

How many placemats can Mandy make, if she has 200 ft of ribbon?

Solve:

200÷30≈7

Thus, she can make 7 placemats.

<h3>Hope it helps & enjoy your day!</h3>

$\huge\textbf{TheStarryNights}$

You might be interested in

there are 98515 trees at Washington Park. if there are 85 aceres of land and the trees are spread out evenly how many trees are

Vlada [557]

There are 1159 trees per acre because 98515/85 = 1159

6 0

3 years ago

–3y9 number of terms

qwelly [4]

Answer and Step-by-step explanation:

$-3y^{9}$

This value above is ONE term. Even though it is made up of more values and stuff, it is all one term BECAUSE they are all connect, so the -3 is with the y by multiplication, and the 9 is with -3y as an exponent of y.

<em><u>#teamtrees #PAW (Plant And Water)</u></em>

5 0

3 years ago

A Poker club has 10 members. A president and a vice-president are to be selected. In how many ways can this be done if everyone

Nesterboy [21]

Answer:

90 different ways

Step-by-step explanation:

We have a total of 10 members, and we want to find how many groups of 2 members we can have, where the order of each member in the group of 2 is important, so we have a permutation problem.

To solve this problem, we need to calculate a permutation of 10 choose 2.

The formula for a permutation of n choose p is:

$P(n, p) = n! / (n - p)!$