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Sunny_sXe [5.5K]

2 years ago

14

Bobby can paint a certain fence in two hours, Zane Zachary can paint the same fence in three hours and Slow Sammy can) t the fen

ce in six hours. If all three boys worked together, how long would it take them to paint the fence?

1 answer:

emmasim [6.3K]2 years ago

3 0

Answer:

11

Step-by-step explanation:

bobby: 2 hours

Zane Zachary: 3 hours

Slow Sammy: 6 hours

2 + 3 + 6 = 11 :)

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Graph the system of linear inequalities, please explain the process in solving this problem so I know how to do ones similar to

Ierofanga [76]

Graph the system of linear inequalities

x + y > 5

- x - y < -5

First we graph x + y >5

Step 1: replace > symbol by = sign

x + y =5

step 2 : Solve the equation for y

x + y =5 (subtract x from both sides)

y = 5 - x

step 3: Now we make a table . plug in some number for x and find out y

x -----> y

-1 -----> 6 ( y=5-x => y=5-(-1)= 6)

0 -----> 5 ( y=5-x => y=5-(0)= 5)

1 -----> 4 ( y=5-x => y=5-(1)= 4)

Step 4: we graph the table.

step 5: Shade the region that satisfies our inequality

x + y > 5. Greater than symbol implies that we shade the graph to the right

Graphing second inequality - x - y < -5

All terms have negative sign . so divide all the terms by -1. When we divide an inequality by -1 its sign changes

- x - y < -5 becomes x + y > 5

Follow the same steps to graph this inequality

After dividing the second equation by -1 , we got the same as the first equation.

So we will get the same graph

Both graphs overlaps

The graph of first and second inequality overlaps

The graph is attached below

4 0

3 years ago

16x²-102X=-36<br> How to write this in Vertex form

boyakko [2]

Answer:

x

Step-by-step explanation:

5 0

3 years ago

50 points. Please quick.

Allisa [31]

Answer:

Condition A.

A rectangle with four right angles

There can be many quadrilaterals satisfying this condition.

Condition B.

A square with one side measuring 5 inches

There can be only one quadrilateral satisfying this condition.

Condition C.

A rhombus with one angle measuring 43°

There can be many quadrilaterals satisfying this condition.

Condition D.

A parallelogram with one angle measuring 32°

There can be many quadrilaterals satisfying this condition.

Condition E.

A parallelogram with one angle measuring 48° and adjacent sides measuring 6 inches and 8 inches.

There can be only one quadrilateral satisfying this condition.

Condition F.

A rectangle with adjacent sides measuring 4 inches and 3 inches.

There can be only one quadrilateral satisfying this condition

Step-by-step explanation:

3 0

3 years ago

Demarcus has to wrap a gift for his friend's birthday party. the gift is in a rectangular box with the dimensions shown below. h

Leya [2.2K]

The gift wrap needed by Damarcus = total surface area of a rectangular box = 1,048 in.².

<h3>What is the Total Surface Area of a Rectangular Box?</h3>

Total surface area (TSA) = 2(wl+hl+hw), where:

l = length
w = width
h = height of the box.

The amount of gift wrap needed to cover the whole box = total surface area of the rectangular box

l = 20 in.

w = 8 in.

h = 13 in.

Plug in the values into the formula for total surface area of a rectangular box:

TSA = 2(8×20 + 13×20 + 13×8)

TSA = 1,048 in.²

Therefore, the gift wrap needed by Damarcus = total surface area of a rectangular box = 1,048 in.².

Learn more about rectangular box on:

brainly.com/question/13103197

6 0

2 years ago

Write an equation for an ellipse centered at the origin, which has foci at (0,\pm\sqrt{63})(0,± 63 )left parenthesis, 0, comma

steposvetlana [31]

Answer:

$\frac{x^{2} }{4312 } + \frac{y^{2} }{8281 }$

Step-by-step explanation:

Since the foci are at(0,±c) = (0,±63) and vertices (0,±a) = (0,±91), the major axis is the y- axis. So, we have the equation in the form (with center at the origin) $\frac{x^{2} }{b^{2} } + \frac{y^{2} }{a^{2} }$ .

We find the co-vertices b from b = ±√(a² - c²) where a = 91 and c = 63

b = ±√(a² - c²)

= ±√(91² - 63²)

= ±√(8281 - 3969)

= ±√4312

= ±14√22

So the equation is

$\frac{x^{2} }{(14\sqrt{22}) ^{2} } + \frac{y^{2} }{91^{2} } = \frac{x^{2} }{4312 } + \frac{y^{2} }{8281 }$

8 0

3 years ago