Answer:
peptidoglycan
Explanation:
Virtually all bacteria contain peptidoglycan in their cell walls; however, archaea and eukaryotes lack peptidoglycan. Various types of cell walls exist in the archaea. Therefore, the absence or presence of peptidoglycan is a distinguishing feature between the archaea and bacteria.
Answer:
Water
Explanation:
Water is a renewable energy source used to generate electricity. A place where this happens at is dams.
Q1. <span>What is the mass of 1 cup of water and 2 teaspoons of salt?
The answer is 258 g.
Density (D) is mass (m) divided by volume (V): D = m/V
So, m = D * V
According to the US units, the volume of 1 cup is: V = 236.6 cm</span>³.
The density of the water is: D = 1 g/cm³.
So, the mass of 1 cup of water is: m = 1 g/cm³ * 236.6 cm³ = 236.6 g.
According to the US units, the volume of 1 teaspoon is: V = 4.93 cm³.
The density of salt is: D = 2.17 g/cm³.
So, the mass of 1 teaspoon of salt is: m = 2.17 g/cm³ * 4.93 cm³ = 10.7 g.
The mass of 1 cup of water and 2 teaspoons of salt is
236.6 g + 2 * 10.7 g = 236.6 g + 21.4 g = 258 g.
Q2. <span>What is the density of 1 cup of water and 2 teaspoons of salt?
</span>The answer is 3.17 g/cm³.
Density (D) is mass (m) divided by volume (V): D = m/V
According to the US units, the volume of 1 cup is: V = 236.6 cm³.
The mass of 1 cup of water from question 1 is: m = 236.6 g.
So, the density of 1 cup of water is: D = 236.6 g / 236.6 cm³ = 1 g/cm³
According to the US units, the volume of 1 teaspoon is 4.93 cm³. The volume of 2 teaspoons is: V = 2 * 4.93 cm³ = 9.86 cm³.
The mass of 1 teaspoon of salt from question 1 is: m = 10.7 g. The mass of 2 teaspoons of salt is: m = 2 * 10.7 g = 21.4 g.
So, the density of 2 teaspoons of salt is: D = 21.4 g / 9.86 cm³ = 2.17 g/cm³
The density of 1 cup of water and 2 teaspoons of salt is:
1 g/cm³ + 2.17 g/cm³ = 3.17 g/cm³
Q3. <span>What is the mass of 1 cup of water and 3 teaspoons of salt?
The answer is 268.7 g.
</span>Density (D) is mass (m) divided by volume (V): D = m/V
So, m = D * V
According to the US units, the volume of 1 cup is: V = 236.6 cm³.
The density of the water is: D = 1 g/cm³.
So, the mass of 1 cup of water is: m = 1 g/cm³ * 236.6 cm³ = 236.6 g.
According to the US units, the volume of 1 teaspoon is: V = 4.93 cm³.
The density of salt is: D = 2.17 g/cm³.
So, the mass of 1 teaspoon of salt is: m = 2.17 g/cm³ * 4.93 cm³ = 10.7 g.
The mass of 1 cup of water and 3 teaspoons of salt is
236.6 g + 3 * 10.7 g = 236.6 g + 32.1 g = 268.7 g.
Q4. <span>What is the density of 1 cup of water and 3 teaspoons of salt?
The answer is 3.17 g/cm</span>³<span>
</span>Density (D) is mass (m) divided by volume (V): D = m/V
According to the US units, the volume of 1 cup is: V = 236.6 cm³.
The mass of 1 cup of water from question 1 is: m = 236.6 g.
So, the density of 1 cup of water is: D = 236.6 g / 236.6 cm³ = 1 g/cm³
According to the US units, the volume of 1 teaspoon is 4.93 cm³. The volume of 3 teaspoons is: V = 3 * 4.93 cm³ = 14.79 cm³.
The mass of 1 teaspoon of salt from question 1 is: m = 10.7 g. The mass of 3 teaspoons of salt is: m = 3 * 10.7 g = 32.1 g.
So, the density of 3 teaspoons of salt is: D = 32.1 g / 14.79 cm³ = 2.17 g/cm³
The density of 1 cup of water and 3 teaspoons of salt is:
1 g/cm³ + 2.17 g/cm³ = 3.17 g/cm³
Q5. What is the mass of 1 cup of water and 4 teaspoons of salt?
The answer is 279.4 g.
Density (D) is mass (m) divided by volume (V): D = m/V
So, m = D * V
According to the US units, the volume of 1 cup is: V = 236.6 cm³.
The density of the water is: D = 1 g/cm³.
So, the mass of 1 cup of water is: m = 1 g/cm³ * 236.6 cm³ = 236.6 g.
According to the US units, the volume of 1 teaspoon is: V = 4.93 cm³.
The density of salt is: D = 2.17 g/cm³.
So, the mass of 1 teaspoon of salt is: m = 2.17 g/cm³ * 4.93 cm³ = 10.7 g.
The mass of 1 cup of water and 4 teaspoons of salt is
236.6 g + 4 * 10.7 g = 236.6 g + 42.8 g = 279.4 g.
Q6. What is the density of 1 cup of water and 4 teaspoons of salt?
The answer is 3.17 g/cm³
Density (D) is mass (m) divided by volume (V): D = m/V
According to the US units, the volume of 1 cup is: V = 236.6 cm³.
The mass of 1 cup of water from question 1 is: m = 236.6 g.
So, the density of 1 cup of water is: D = 236.6 g / 236.6 cm³ = 1 g/cm³
According to the US units, the volume of 1 teaspoon is 4.93 cm³. The volume of 4 teaspoons is: V = 4 * 4.93 cm³ = 19.72 cm³.
The mass of 1 teaspoon of salt from question 1 is: m = 10.7 g. The mass of 4 teaspoons of salt is: m = 4 * 10.7 g = 42.8 g.
So, the density of 3 teaspoons of salt is: D = 42.8 g / 19.72 cm³ = 2.17 g/cm³
The density of 1 cup of water and 4 teaspoons of salt is:
1 g/cm³ + 2.17 g/cm³ = 3.17 g/cm³
Answer:
A eukaryote is an organism with complex cells, or a single cell with a complex structures. In these cells the genetic material is organized into chromosomes in the cell nucleus. Animals, plants, algae and fungi are all eukaryotes. There are also eukaryotes amongst single-celled protists.
Nearly 99% of the mass of your human body consists of just 6 chemical elements: oxygen, carbon, hydrogen, nitrogen, calcium, and phosphorus. Another 5 elements make up most of the last percentage point: potassium, sulfur, sodium, chlorine, and magnesium.
