Answer:
The question is not improper, But I will try to explain your doubt.
- The pot and part of stove are obviously in contact with each other. It is known <em>as conduction</em>
- The pot on gas stove burner, the air above the stove is heated and because it is gas moves upwards, this is <em>convection</em>. The bottom of the pot and surface of the stove are not 100% flat. Thats why there will be little pockets of air underneath the pot,even if you place it on the stove.
If we heat up the stove as much as then it turns to red, this visible sign is known as<em> radiation.</em>
<em>Therefore all the 3 kinds of heat transfer takes place</em>
Answer:
The first model of the atom was developed by JJ Thomson in 1904, who thought that atoms were composed purely of negatively charged electrons. This model was known as the 'plum pudding' model.
Explanation:
Sorry that's all I know ♂️
Answer:
Explanation:
We have a metal ring of diameter
d = 4.2cm = 0.042m
r = d/2 = 0.021m
And it is place between the north pole and south pole of a large magnet with the plane of it's area perpendicular to the magnetic field.
Given that the magnetic field is
B = 1.12 T
The rate of decrease of magnetic field is 0.2T/s, since it is decrease then,
dB/dt = -0.2 T/s
The induce electric field is given as,
From faradays law
ε = ∫E•dl = -dΦ/dt
Magnetic flux is given as
Φ = BA
Φ = πr²×B = πr²B
Also, ∫E•dl = E×2πr = 2πrE
So,
∫E•dl = -dΦ/dt
2πrE = -d(πr²B) / dt
r is a constant, then
2πrE = -πr² dB/dt
Divide both side by πr
2E = -r dB/dt
E = -r dB/dt / 2
E = -0.021 × -0.2 / 2
E = 0.0021 V/m
The magnetic field point from north to south pole and it is decreasing and this means that the magnetic flux is also decreasing, so the induce magnetic field must point in the same direction of the original magnetic field, so the induce current circulate counter-clockwise as viewed from the south pole
Answer:
25 ohms
Explanation:
Hi there!
Ohm's law states that 
where V is voltage, I is current and R is resistance.
Plug the given information into Ohm's law (V=50, I=2) and solve for R
Divide both sides by 2 to isolate R
Therefore, there are 25 ohms of resistance present in this circuit.
I hope this helps!
