Answer:
The magnitude of displacement is 56.54 m
The direction of the displacement is along the line joining the two vectors.
Explanation:
The resultant displacement is always the line joining the initial and final position of the vectors.
As in figure,
the vector AB = 35 m
the vector BC = 15 m
the angle between AB and AC = 25' (minutes)
the resultant vector AC = ?
The resultant vector is given by the formula
AC² = AB² + BC² + 2 AB BC Cos θ
Substituting the values in the equations,
AC² = 35² + 15² + 2 x 35 x 15 x Cos 25'
= 56.54
Therefore, the magnitude of displacement is 56.54 m
The direction of the displacement is along the line joining the two vectors.
Total distance is 28+12+34=74km=74000m.
Total time is 20+8+25 minutes=53 minutes=53×60=3180 secs.
Average speed is 74000/3180=23.27 m/s.
Answer:
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Explanation:
Answer:
The magnitude of each force is 1309 N and 105 N
Explanation:
The reaction at each lifter due weight and overturning effect (R₁, R₂) is given as:

g = 9.8 m/s²

Resolving the reactions to the vertical direction, we get:

The magnitude of each force is 1309 N and 105 N