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bagirrra123 [75]
3 years ago
14

lightning and thunder both occur at the same time why do you see the Lightning before you hear the thunder

Physics
2 answers:
taurus [48]3 years ago
8 0

Great question!

Thunder and lightning happen at the same time, but because light travels faster than sound, we see lightning before we hear thunder.

denis23 [38]3 years ago
5 0

Because the light from it travels to you about 874 thousand times
as fast as the sound does, so the hearing part falls behind the seeing
part.
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An electron moves in the plane of this screen toward the top of the screen. A magnetic field is also in the plane of the screen
Ad libitum [116K]

Answer: the direction of the magnetic force on the electron will be moving out of the screen, perpendicular to the magnetic field.

Explanation:

The magnetic force F on a moving electron at right angle to a magnetic field is given by the formula:

F = BqVSinØ

If an electron moves in the plane of this screen toward the top of the screen. A magnetic field is also in the plane of the screen and directed toward the right. Then, the direction of the magnetic force on the electron will be perpendicular to the magnetic field

According to the Fleming's left - hand rule, the direction of the magnetic force on the electron will be moving out of the plane of the screen.

6 0
3 years ago
A 1.0 m string with a 5 g stopper on the end is whirled in a vertical circle. The speed of the stopper is 8 m/s at the top of th
Andrew [12]

Answer:

Explanation:

A )

At the bottom of the circle , the potential energy of the stopper is converted into kinetic energy

1/2 m V² = mg x 2r + 1/2 mv²

m is mass of stopper , V is velocity at the bottom , r is radius of the circular path which is length of the string , v is velocity at the top

1/2  V² = g x 2r + 1/2 v²

 V² = g x 4r +  v²

 V² = 9.8 x 4 +  8²

V² = 103.2

V = 10.16 m/s

B )

If T be the tension at the top

Net downward force

= mg + T . This force provides centripetal force for the circular motion

mg +T = mv² / r

T =   mv²/r -mg

= m ( v²/r - g )

= .005 ( 8²/1 -g )

= .005 x 54.2

= .27 N .

C ) At the bottom

Net force = T  - mg , T is tension at the bottom , V is velocity at bottom

T-mg = mV²/r

T = m ( V²/r +g )

= .005 ( 10.16²/1 +9.8)

= .005 x 113

= .56 N .

3 0
3 years ago
An empty plate capacitor is connected between the terminals ofa 9.0 V battery and charged up. The capacitor is then disconnected
777dan777 [17]

Answer:

The new voltage between the parallel plates of the capacitor is 18V, because for a constant electric field, doubling the space between the parallel capacitor plates, will also double the potential difference (voltage) between the plates.

Explanation:

ΔV = E*Δd

Where;

ΔV is the change in potential difference

Δd is the change in the distance between the parallel plates

E is the electric field potential.

Assuming a constant electric field; E = \frac{v}{d} , then; \frac{v_1}{d_1} =\frac{v_2}{d_2}

when the spacing between the capacitor plates is doubled, d₂ = 2d₁

v₂ = (v₁*d₂)/(d₁)

v₂ = (v₁*2d₁)/(d₁)

v₂ = 2v₁

v₂  = 2(9) = 18 V

Therefore, for a constant electric field, doubling the space between the parallel capacitor plates, will also double the potential difference (voltage).

5 0
3 years ago
(A) how much work is done when you push a crate horizontally with 100 N across a 10-m factory floor?
Mila [183]

Answer:

A) 1000 joules

Explanation:

In general work is given by the equation:

W=\intop_{a}^{b}\overrightarrow{F}\cdot d\overrightarrow{s} (1)

A) With \overrightarrow{s} the displacement and \overrightarrow{F} the force applied, because the force and the displacement are parallel (the crate is pushed horizontally) \overrightarrow{F}\cdot d\overrightarrow{s} is simply F\,ds, and because the path is a straight line and the force is constant work is:

W=FS (2),

W=(100)(10)=1000\,J

B) The work-energy theorem says that the total work on a body is equal to the change on kinetic energy:

W_{tot}=\varDelta K (3)

The total work on the crate is the work done by the push and plus the work of the friction W_{tot}=W + W_{f} (4) , as (A) because forces are parallel to the displacement W= FS (5) and W_{f}=-fS (6), the due friction always has negative sign because is opposite to the displacement, using (6), (5) and (4) on (3):

FS-fS=\varDelta K (3)

1000-(70)(10)=300\,J

C) The energy is lost by friction, so the amount of energy turned into heat is the work the friction does:

Q=fS=(70)(100)=700\,J (3)

6 0
4 years ago
CD bisects AB at point G. If AE = BE, which equation must be true?
ratelena [41]
AG = BG equation must be true
8 0
4 years ago
Read 2 more answers
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